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Doss [256]
3 years ago
5

What is a gravitational wave and why was it so hard to detect?

Physics
1 answer:
Alika [10]3 years ago
5 0

Answer:

gravitational waves are ripples in spece-time caused primarily when objects are accelerated and the energy for the acceleration is transpoted as gravitational radiation.

they are difficult to detect because they require very sensitive technology or you will have to wait unitl black holes collide.

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Newton’s Laws of Motion are absolute in classical physics. One example that uses all three laws simultaneously is the firing of
Debora [2.8K]
I think that by "Classical physics" is meant low speed things. By low speed, I think is meant speed far below very roughly half the speed of light, so that Relativistic, special or general, effects can be ignored. Or at least it is hoped that they can be ignored. 
Fire extinguishers and rockets get propelled by forcing out large amounts of material (gases under very high pressure) through a nozzle, and the RECOIL from that propels something forward. So, if the action is the ejection of material, the reaction (recoil) is the ejector moving along the same line in the other direction. And that's an example of Newton's third law. 
Given a propulsion system, the magnitude of the force recoiling on the ejector will change the momentum of the ejector, often written as the equation F=ma where F is the force, m is the mass being accelerated, and a being the acceleration.
Just as something will stay still until it is moved - inertia - so once set in uniform motion in a straight line, the thing will continue in that motion, theoretically for ever or until something alters its momentum. Newton's first law is to the effect of "every body continues in a state of rest or uniform motion in a straight line unless acted on by a resultant external force". Which, I think, is where the concept of inertia stems from. 
I think that the above mostly tcuches on the 3 laws.Any more help needed, please ask.
6 0
3 years ago
Read 2 more answers
Please help!!!!
Dafna11 [192]

The intensity of the electric field is 30,000 N/C

Explanation:

The strength of the electric field produced by a single-point charge is given by the equation

E=k\frac{q}{r^2}

where:

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q is the magnitude of the charge

r is the distance from the charge

In this problem, we have:

q=3\cdot 10^{-9}C is the magnitude of the charge

r = 3 cm = 0.03 m is the distance at which we are calculating the field intensity

Substituting, we find:

E=(8.99\cdot 10^9)\frac{3\cdot 10^{-9}}{(0.03)^2}=30,000 N/C

Learn more about electric field:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

5 0
3 years ago
A material the resists the flow of electrons is called a
svp [43]
An insulator which is also called a 'dielectric'.
8 0
3 years ago
Your physics textbook is sliding to the right across the table draw the vectors starting at the black dot. the location and orie
liberstina [14]
You would take a black dot at the top right of the y axis and dray it to the the far right of your x axis. hope this helps have a nice day and God bless
6 0
3 years ago
A 0.00287 C charge is 6.52 m from
yKpoI14uk [10]

Answer:

I know dude

Explanation:

-22000

7 0
3 years ago
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