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Doss [256]
3 years ago
5

What is a gravitational wave and why was it so hard to detect?

Physics
1 answer:
Alika [10]3 years ago
5 0

Answer:

gravitational waves are ripples in spece-time caused primarily when objects are accelerated and the energy for the acceleration is transpoted as gravitational radiation.

they are difficult to detect because they require very sensitive technology or you will have to wait unitl black holes collide.

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What is the resistivity of a wire of 1.3 mm diameter, 2.3 m length, and 61 ms resistance. Number Units The number of significant
kakasveta [241]

Answer:

\rho = 3.68 *10^{-8} Ω. m

Explanation:

The resistance is given as

R = \frac{\rho L}{A}

Where A IS Cross sectional area of wire= \pi r^{2}

therefore resistivity \rho can be wrtten as

\rho = \frac{\pi Rd^{2}}{4L}

Putting all value to get resistivity value\rho =\frac{\pi* 61*10^{-3}* (1.33*10^{-3})^{2}}{4*2.3}

\rho = 3.68 *10^{-8} Ω. m

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Generators use a magnetic field of which of the following to produce an electric current?
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A wave has a wavelength of 20 mm and a frequency of 5 Hz what is the speed?
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The answer is 100mm/s. I hope this helps :)

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Select the appropriate shape for the given volume form
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3 0
2 years ago
A hydrogen atom in the n=7 state decays to the n=4 state. what is the wavelength of the photon that the hydrogen atom emits? use
frez [133]

A hydrogen atom in the n=7 state decays to the n=4 state. The wavelength of the photon that the hydrogen atom emits is 4592.59nm.

The Energy of photon is the energy possessed by a photon when it moves from a high energy level to a low energy level. It emits a photon of a certain wavelength. The following relation can be used to find out the relation between the energy levels and the energy possessed:

E = 13.6 × Z² (1/n₂² - 1/n₁²) eV

where, n₁ is the initial energy level i.e. n₁ =7

            n₂ is the higher energy level i.e. n₂ = 4

            E is the energy possessed

            Z is the atomic number, Z = 1 for H-atom

Subsituting in above equation,

E = 13.6 (1/16 - 1/49) eV

E = 0.27 eV

We know that,

E = hc / λ  

where, h is Planck constant

           c is speed of light

            λ is wavelength

On subsituting,

0.27 eV = 1240/ λ

⇒ λ = 4592.59 nm

Hence, the wavelength of photon emitted by Hydrogen atom is 4592.59nm.

Learn more about Energy of Photon here, brainly.com/question/2393994

#SPJ4

 

5 0
1 year ago
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