Answer:
0.15 L
Explanation:
Step 1. Calculate the <em>moles of KF.</em>
Molar mass = 58.10 g/mol
Moles of KF = 8.0 × 1/58.10
Moles of KF = 0.138 mol KF
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Step 2. Calculate the <em>volume of KF
</em>
c = n/V Multiply both sides by V
V = 0.138 × 1/0.89
V = 0.15 L
Answer:
C. 0.4.
Explanation:
<em>∵ mole fraction of acetic acid (X acetic acid) = (no. of moles acetic acid)/(total no. of moles) = (no. of moles acetic acid)/(no. of moles of acetic acid + no. of moles of water).</em>
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- no. of moles of acetic acid = 2, no. of moles of water = 3.
- Total no. of moles = no. of moles of acetic acid + no. of moles of water = 2 + 3 = 5.
<em>∴ mole fraction of acetic acid (X acetic acid) = (no. of moles acetic acid)/(total no. of moles) =</em> (2)/(5)<em> = 0.4.</em>
Since that E°cell =E°cathode - E°anode then
0.62V = 0.34 - E°anode
Therefore E° anode is = -0.28V
Answer:
The way you can know which compound in a solution is a solvent is by usually just determining which substance is a solute and which is a solvent. The solute is when it is dissolved and it takes on the characteristics of the solvent.
Explanation:
Hope this helps!
