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Karo-lina-s [1.5K]
2 years ago
11

Pls fast,i need it ..............................

Mathematics
1 answer:
Ghella [55]2 years ago
6 0

Answer:

hints to solve each. partial answer due to lack of time, hope it helps!

Step-by-step explanation:

1)

a) solve ():

5 \sqrt{3} + 7 \sqrt{3} - 9 \sqrt{3} - 6 \sqrt{3} + 12 \sqrt{3} - 10 \sqrt{3} =

\sqrt{3} . (5 +7-9-6+12-10)

b) use \sqrt{6\\} = \sqrt{3\\}\\\\\sqrt{2\\}\\\\

c) use \sqrt{20\\} = \sqrt{4\\}\\\\\sqrt{5\\}\\\\ = 2\sqrt{5\\}\\\\

use \sqrt{8\\} = \sqrt{4\\}\\\\\sqrt{2\\}\\\\ = 2\sqrt{2\\}\\\\

2)

a) use \sqrt{30\\} = \sqrt{6}\sqrt{5}

use \sqrt{30\\} = \sqrt{6}\sqrt{4} = 2\sqrt{6}

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GUYS I MESSED UP ON THE LAST ONE PLEASE HELP ME AGAIN what algebraic expression represents GK
Zielflug [23.3K]

Answer:

GK = 9x-5

Step-by-step explanation:

GK = GH +HJ + JK

= (GJ - HJ) + (HJ) + (HK - HJ)

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= (3x+5x+x)+(-3-2)

GK = 9x-5

7 0
2 years ago
Find the product:<br><br> (r+2)(r-5)(r-2)(r+5)<br><br> Please show all steps.<br><br> 15 points.
Virty [35]

Hello from MrBillDoesMath!

Answer:

r^4- 29r^2 + 100

Discussion:

Rearrange the terms in the product as follows:

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(r^2 - 4) * (r^2-25) =

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r^4- 29r^2 + 100

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7 0
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Read 2 more answers
An exponential random variable has a standard deviation of 16. Calculate The probability that it takes on a value &lt; 11. Use 3
antiseptic1488 [7]

Answer:

P(X

And using the cdf we got:

P(X

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}, x>0

And 0 for other case. Let X the random variable that represent the random variable of interest and we know that the distribution is given by:

X \sim Exp(\lambda)

We know the variance on this case given by :

Var(X) = \frac{1}{\lambda^2}

So then the deviation is given by:

Sd(X) = \frac{1}{\sqrt{\lambda}}

And if we solve for \lambda we got:

\lambda = (\frac{1}{16})^2 = \frac{1}{256}

The cumulative distribution function for the exponential distribution is given by:

F(x) = 1- e^{-\lambda x}

Solution to the problem

And for this case we want to find this probability:

P(X

And using the cdf we got:

P(X

5 0
2 years ago
Find such a coefficient for a for the linear equation ax-y=4, so that the graph of the equation would pass through the point M(3
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Answer:

Can you send me a picture I am confused

Step-by-step explanation:

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