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3 years ago

The hockey stick hits the puck forward. Give the reaction force

Physics

1 answer:

weqwewe [10]3 years ago

3 0

I think the puck pushes the stick backwards

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A 594 Ω resistor, an uncharged 1.3 μF capacitor, and a 6.53 V emf are connected in series. What is the current in milliamps afte

ivanzaharov [21]

Answer:

6.88 mA

Explanation:

Given:

Resistance, R = 594 Ω

Capacitance = 1.3 μF

emf, V = 6.53 V

Time, t = 1 time constant

Now,

The initial current, I₀ = $\frac{\textup{V}}{\textup{R}}$

I₀ = $\frac{\textup{6.53}}{\textup{594}}$

I₀ = 0.0109 A

also,

I = $I_0[1-e^{-\frac{t}{\tau}}]$

here,

τ = time constant

e = 2.717

on substituting the respective values, we get

I = $0.0109[1-e^{-\frac{\tau}{\tau}}]$

I = $0.0109[1-2.717^{-1}]$

I = 0.00688 A

I = 6.88 mA

5 0

3 years ago

How might a location's altitude influence it's climate?

UNO [17]

Answer:

You will discover that at high altitude, there is cold and the opposite is experienced when you go deep down the sea. However, the reason elevation affects climate and temperature gets colder is this. As you go higher up, the atmosphere experiences less pressure.

Explanation:

3 0

3 years ago

What's the definition of altitude?

OleMash [197]

Altitude is the height of something or the point of sea level or ground level.
hope i helped!!

6 0

3 years ago

Read 2 more answers

A car travels at an average speed of 60 km / h for 15 minutes. How far does the car travel in 15 minutes?

salantis [7]

Answer:

15km

Explanation:

Given parameters:

Average speed = 60km/hr

Time taken = 15min

Unknown:

Distance = ?

Solution:

The distance traveled can de derived using the expression below;

Distance = Average speed x time taken

Now let us convert the time to hr;

60min = 1hr

15min = $\frac{15}{60}$ = 0.25hr

Distance = 60km/hr x 0.25hr = 15km

6 0

3 years ago

The magnitude of vector λa is 5. Find the value of λ, if: a = (−6, 8)

Nata [24]

Given :

$\: \:$

$\color{pink}{\rm \: The \:magnitude \:of \:vector\: λa\: is \: {\bold5\:}}$

$\:$

$\color{green}{\rm \: a = (−6, 8)}$

$\:$

To Find :

$\: \:$

$\orange{ \rm\: value \: of \: \bold{ λ \: }}$

$\: \:$

$\rm \: The \: magnitude \: of \: the \: vector \: a \: is \: ||a|| = \sqrt{(-6)^2+ 8^2)} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \rm = \sqrt{( 36+64)} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:\:\: \: \:\:= \rm\sqrt{100} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:\\\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:\: \rm \underline{\boxed{\red{ \: = 10 \: }}} \green✓$

$\: \:$

$\rm \: Therefore, \: λ = \cancel{\frac{5}{10} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \underline { \: \boxed{ \red{\: \rm = 0.5\:}}}{ \green ✓ }$

Hope helps ~

$\color{purple}\frak{SarcasticSmileeᥫ᭡}$

4 0

2 years ago