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elena-14-01-66 [18.8K]
3 years ago
12

What do you like about engaging to different reereational activities

Physics
1 answer:
Novay_Z [31]3 years ago
6 0

Answer:

What I like the most about engaging to different recreational activities is that these contribute to my entertainment and relax after working.

That is, recreational activities allow individuals to abstract from their daily responsibilities, encouraging distraction and concentration of the individual on issues of less importance, allowing them to relax.

Therefore, in my case I love that different recreational activities, such as sports or social gatherings, allow me to abstract from my responsibilities and allow me to enjoy moments of fun.

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A 3.2 kg particle starts from rest at x = 0 and moves under the influence of a single force Fx = 4 + 15.7 x − 1.5 x 2 , where Fx
garik1379 [7]

Answer:

Explanation:

Work: This can be defined as the product of force and distance. The unit of work is Joules (J). it can be expressed mathematically as

W = F×d

or

W = \int\limits^b_a {Fx} \, dx.................................. Equation 1

Where b = upper limit, a = lower limit, Fx = expression of force.

<em>Given: a = 0 , b = 1.3 m, Fx = 4 + 15.7x - 1.5x²</em>

Substituting these values into equation 1

<em>W = \int\limits^a_b {(4 + 15.7x - 1.5x^{2} )dx} \,</em>

W = ᵇ[4x + 15.7x²/2-1.5x³/3 +C]ₐ

Work = upper limit - lower limit

Work = ᵃ[4x + 15.7x²/2 - 1.5x³/3 +C] - [4x + 15.7x²/2 + 1.5x³/3 +C]ᵇ............... Equation 2

Substituting the values of a and b into equation 2

Work = [4(1.3) + 15.7(1.3)²/2-1.5(1.3)³/3 + C] - [0 +C]

Work = [5.2 + 26.53 -3.29 + C] - C

Work = 28.44 J

Work done by the force = 28.44 J.

8 0
3 years ago
A spaceship orbiting earth flies to the moon. How is the gravitational force pulling on the spaceship related to the distance th
____ [38]
The correct answer is "As the distance from the earth increases, the gravitational pull on the spaceship would decrease."

In fact, the gravitational force (attractive) exerted by the Earth on the spaceship is given by
F=G \frac{Mm}{d^2}
where G is the gravitational constant, M the Earth's mass, m the mass of the spaceship and d the distance of the spaceship from the Earth. As we can see from the formula, as the distance d between the spaceship and the Earth increases, the gravitational force F decreases, so answer D) is the correct one.
3 0
3 years ago
Pls help 100 points plssssssss
natima [27]

Answer:

d

Explanation:

8 0
2 years ago
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Brrunno [24]

As we know that power is defined as rate of work done

so we will have

P = \frac{Work}{time}

so in order to increase the power as per above formula we know that either we need to increase the work or we need to decrease the time to complete that work

So here the correct answer will be

increase the work being done or decrease the time in which the work is completed.

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The weight of an object on Earth is 350 newtons. On Mars, the same object would weigh 134 newtons. What is the acceleration due
sineoko [7]
W = mg = 350 newton
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on mars
W = mg = 134 newton
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