Question

dinitrogen pentoxide decomposes to form nitrogen dioxide oxygen, following the equation 2N2O5 -> 4NO2. at a certain time point, N2O5 is being consumed at the rate of 0.1 M/s. what’s the rate of production of NO2 and O2 at the same time point?

Answer 1

Answer:

NO2 is produced at 0.2 M/s, and O2 is produced at 0.05 M/s.

Explanation:

Answer 2

Rate of production of NO₂ = 0.2 M/s

Rate of production of O₂ = 0.05 M/s

Further explanation

Given

The rate of N₂O₅ : 0.1 M/s

Reaction

2N₂O₅⇒4NO₂+O₂

Required

The rate of production of NO₂ and O₂ at the same time point

Solution

Rate of disappearance of N₂O₅ = reaction rate x coefficient of N₂O₅

0.1 M/s=reaction rate x 2

reaction rate = 0.05 M/s

The rate of production of NO₂=

Rate of production of NO₂ = reaction rate x coefficient of NO₂

Rate of production of NO₂ = 0.05 M/s x 4

Rate of production of NO₂ = 0.2 M/s

The rate of production of O₂=

Rate of production of O₂ = reaction rate x coefficient of O₂

Rate of production of O₂ = 0.05 M/s x 1

Rate of production of O₂ = 0.05 M/s