Answer:
i) acceleration from B to D is 0, because the velocity is constant (stays the same)
ii) whatever units of distathat might be, we can calculate the number:
for 4 time-steps (2 to 6) the velocity is 6 per time step, that makes 24 distance units in these 4 time steps. it's the same the area underneath the graph.
there is also the vertical line from 0 to 2. we can calculate that distance like the area of a triangle with 2*6 / 2 = 6
the total distance from 0 to D is therefore 30
Answer:
(A)
Explanation:
P1 = MVcos 30
P2 = MVcos 30
️P = -2 mvcos 30
️P = - square root of 3 mv
f1 = 2mv/ ️t
force on the wall = 2
f2 = square root of 3mv/ ️t, so f1 > f2
Position of paul with respect to john is given as
14 m due west of john
position of George with respect to Paul is given as 36 m in direction 37 degree south of east
now we need to find the position of George with respect to John
![r_{GJ} = r_G - r_j[\tex]now for the above equation we can add the two equations[tex]r_{Gj} = -14\hat i + 36 cos37\hat i - 36sin37\hat j](https://tex.z-dn.net/?f=r_%7BGJ%7D%20%3D%20r_G%20-%20r_j%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3Enow%20for%20the%20above%20equation%20we%20can%20add%20the%20two%20equations%3C%2Fp%3E%3Cp%3E%5Btex%5Dr_%7BGj%7D%20%3D%20-14%5Chat%20i%20%2B%2036%20cos37%5Chat%20i%20-%2036sin37%5Chat%20j)
so the magnitude is given as
and direction is given as
<em>so it is 26.2 m at an angle 55.75 degree South of east</em>
Answer:
Explanation:
Person suffering from myopia is unable to see objects beyond 50 cm because far point of his vision is 50 cm . He requires a concave lens
( diverging lens ) to correct his vision .
After using the lens ,
ray of light coming from far off place will appear to be coming from 50 cm after refraction through lens so it will be focused on retina .
object distance u = ∝
image distance v = - 50 cm
focal length f = ?
1 / v - 1 / u = 1 /f
- 1 / 50 - 1 / ∝ = 1 / f
- 1 / 50 = 1 / f
f = - 50 cm
focal length is negative so len is concave.
He requires concave lens of focal length 50 cm .
