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Semenov [28]
3 years ago
5

An empty beaker weighs 20g and when filled with kerosene weighs 60g. If the volume of the kerosene is 15cm3, calculate the densi

ty of the kerosene
Chemistry
1 answer:
oee [108]3 years ago
6 0

Answer:

2.7 g/cm³

Explanation:

Step 1: Calculate the mass of kerosene

The mass of the full beaker (mFB) is equal to the sum of the masses of the empty beaker (mEB) and the mass of the kerosene (mK).

mFB = mEB + mK

mK = mFB - mEB

mK = 60 g - 20 g = 40 g

Step 2: Calculate the density of kerosene

Density (ρ) is an intrinsic property of matter. It can be calculated as the quotient between the mass of kerosene and its volume.

ρ = m/V

ρ = 40 g/15 cm³ = 2.7 g/cm³

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Answer:

12 oxygen atoms are in 4 molecules of HNO3?

Explanation:

the amounts of atoms of all the component in HNO3, which are 1 atom of Hydrogen, 1 atom of Nitrogen and 3 atoms of Oxygen.

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Aqueous hydrochloric acid reacts with solid sodium hydroxide to produce aqueous sodium chloride and liquid water . If of water i
Kaylis [27]

Answer:

87.9%

Explanation:

Balanced Chemical Equation:

HCl + NaOH = NaCl + H2O

We are Given:

Mass of H2O = 9.17 g

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Mass of NaOH = 43.6 g

First, calculate the moles of both HCl and NaOH:

Moles of HCl: 21.1 g of HCl x 1 mole of HCl/36.46 g of HCl = 0.579 moles

Moles of NaOH: 43.6 g of NaOH x 1 mole of NaOH/40.00 g of NaOH = 1.09 moles

Here you calculate the mole of H2O from the moles of both HCl and NaOH using the balanced chemical equation:

Moles of H2O from the moles of HCl: 0.579 moles of HCl x 1 mole of H2O/1 mole of HCl = 0.579 moles

Moles of H2O from the moles of NaOH: 1.09 moles of HCl x 1 mole of H2O/1 mole of NaOH = 1.09 moles

From the calculations above, we can see that the limiting reagent is HCl because it produced the lower amount of moles of H2O. Therefore, we use 0.579 moles and NOT 1.09 moles to calculate the mass of H2O:

Mass of H2O: 0.579 moles of H2O x 18.02 g of H2O/1 mole of H2O = 10.43 g

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3 years ago
Match each term to its description. (3 points)
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Answer:   Limiting reactant = 3  

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An excess reactant is a reactant present in an amount in excess of that required to combine with all of the limiting reactant. It follows that an excess reactant is one remaining in the reaction mixture once all the limiting reactant is consumed.

The limiting reagent is the reactant that is completely used up in a reaction, and thus determines when the reaction stops. From the reaction stoichiometry, the exact amount of reactant needed to react with another element can be calculated

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Why is it impossible for scientists to use macroscopic tools such as scissors to create nanoparticles?.
swat32

Nano particles are very small and can not be seen with eyes measuring between 1 to 100 n m. Because of their small size, they can't be made from macroscopic tools.

<h3>What are particles? </h3>

These refers to those particles whose size lie between 1 to 100 n m. They are extremely small and often can not be seen with the eyes.

Owing to the fact that these particles are very small , they can not be created with very large  substances.

Learn more about particles: brainly.com/question/9220200?

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Calculate the amount of heat needed to evaporate 235.0 grams of water from 25.0°C to 100.0°C.
steposvetlana [31]
I hope this helps answer your question. :)

These problems are very hard to do digitally so I would recommend trying to practice these types of problems on paper :)

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