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earnstyle [38]
3 years ago
10

g A simply supported beam is subjected to a distribution of force per length given by the polynomial form: q(x)=Axn . Calculate

the deflection v(x) in the beam, where flexural rigidity is EI. (Hint- Find RA and RB first. And start with fourth order equation. Solve for integration constants and write the final equation clearly) (20 points)

Physics
1 answer:
nignag [31]3 years ago
5 0

Answer:

V =1/EI(-Ax^n+y/(n+1)(n+2)(n+3)(n+y)+AL^n+1 x^3/6(n+1)(n+2)+AL^n+3(6-(n+3)(n+4)x/6(n+1)(n+2)(n+3)(n+4))

Explanation:

Please look at attachment for step by step solution and guide.

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Several wires of varying thickness are all made of the same material and all have the same length. If the wires are arranged in
aev [14]

Answer:

Option A is correct.

The wires will be arranged in order of increasing resistance.

Explanation:

The resistance of a wire is given by

r = (ρl)/A

where r = resistance of the wire

ρ = resistivity of the wire

L = length of the wire

A = cross sectional area of the wire

Provided all the other parameters are constant, resistance is inversely proportional to cross sectional area

r ∝ (1/A)

And the the cross sectional Area of the wire increases with increase in thickness & decreases with thickness

So, decreasing thickness ----> Decreasing Cross sectional Area ----> Increasing resistance.

5 0
3 years ago
Speed is usually what
kolbaska11 [484]

Answer:

measured in GHz?

Explanation:

im not sure what the context is it depends on what your lesson is on

3 0
3 years ago
Two cars cover the same distance in a straight line. Car a covers the distance at a constant velocity. Car b starts from rest an
Artyom0805 [142]

a) For the motion of car with uniform velocity we have , s = ut+\frac{1}{2}at^2, where s is the displacement, u is the initial velocity, t is the time taken a is the acceleration.

In this case s = 520 m, t = 223 seconds, a =0 m/s^2

Substituting

       520 = u*223\\ \\u = 2.33 m/s

 The constant velocity of car a = 2.33 m/s

b) We have s = ut+\frac{1}{2} at^2

s = 520 m, t = 223 seconds, u =0 m/s

Substituting

      520 = 0*223+\frac{1}{2} *a*223^2\\ \\ a = 0.0209 m/s^2

Now we have v = u+at, where v is the final velocity

Substituting

        v = 0+0.0209*223 = 4.66 m/s

So final velocity of car b = 4.66 m/s

c) Acceleration = 0.0209 m/s^2

7 0
3 years ago
7 the density of the american white oak tree is 752 kilograms per cubic meter. if the trunk of an american white oak tree has a
alexdok [17]

First, we determine the volume of the trunk by finding first the radius from the circumference through the equation,

<span>                                                            C = 2πr</span>

<span>                                                            r = C/2π</span>

Substituting the known values,

<span>                                                            r = 4.5/2π = 0.716 m</span>

Then, we calculate for the volume through the equation,

<span>                                                            V = πr2h</span>

<span>                                                V = π(0.716 m)2(8m) = 12.9 m3</span>

Multiplying the calculated value to the density will give the mass as,

<span>                                                Mass = (12.9 m3)(752 kg/m3) = <span>9699.36 kg</span></span>

3 0
3 years ago
You drop two balls from a tower, one of mass m and the other of mass 3m.
neonofarm [45]
The potential energy that the ball has at the top of the tower is its kinetic energy when it hits the ground. The second ball has more potential energy at the top, because you did more work on it to carry it up there. So it has more KE at the bottom. (A)
3 0
3 years ago
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