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earnstyle [38]
3 years ago
10

g A simply supported beam is subjected to a distribution of force per length given by the polynomial form: q(x)=Axn . Calculate

the deflection v(x) in the beam, where flexural rigidity is EI. (Hint- Find RA and RB first. And start with fourth order equation. Solve for integration constants and write the final equation clearly) (20 points)

Physics
1 answer:
nignag [31]3 years ago
5 0

Answer:

V =1/EI(-Ax^n+y/(n+1)(n+2)(n+3)(n+y)+AL^n+1 x^3/6(n+1)(n+2)+AL^n+3(6-(n+3)(n+4)x/6(n+1)(n+2)(n+3)(n+4))

Explanation:

Please look at attachment for step by step solution and guide.

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3 years ago
PLEASE HELP
Anvisha [2.4K]

The speed of the rock at 20 m is 34.3 m/s

Explanation:

We can solve this problem by using the law of conservation of energy: the mechanical energy of the rock, sum of its potential energy + its kinetic energy) must be conserved in absence of air resistance. So we can write:

U_i +K_i = U_f + K_f

where :

U_i is the initial potential energy

K_i is the initial kinetic energy

U_f is the final potential energy

K_f is the final kinetic energy

The equation can also be rewritten as  follows:

mgh_i + \frac{1}{2}mu^2 = mgh_f + \frac{1}{2}mv^2

where:

m = 100 kg is the mass of the rock

g=9.8 m/s^2 is the acceleration of gravity

h_i = 80 is the initial height

u = 0 is the initial speed  (the rock starts at rest)

h_f = 20 m is the final height of the rock

v is the final speed when h = 20 m

And solving for v, we find:

v=\sqrt{2g(h_i-h_f)}=\sqrt{2(9.8)(80-20)}=34.3 m/s

Learn more about kinetic energy and potential energy here:

brainly.com/question/6536722

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#LearnwithBrainly

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