Answer:
Approximately 
(given that the magnitude of this charge is 
.)
Explanation:
If a charge of magnitude 
is placed in an electric field of magnitude 
, the magnitude of the electrostatic force on that charge would be 
.
The magnitude of this charge is 
. Apply the unit conversion 
:
.
An electric field of magnitude 
would exert on this charge a force with a magnitude of:
.
Note that the electric charge in this question is negative. Hence, electrostatic force on this charge would be opposite in direction to the the electric field. Since the electric field points due south, the electrostatic force on this charge would point due north.
metamorphic, sedimentary, igneous
Answer:
1. What type of wave is sound?
2.Does sound need a medium to travel through?
3. What are the properties of sound waves?
Explanation:
1. The type of waves sound are is mechanical waves.
2. Sound needs a solid, liquid or gas (material medium) to travel through.
3. I believe they are wavelength, amplitude, frequency, time period and velocity.
I apologize if it is incorrect-
I hope it helps! Have a great day!
Anygays-
Answer:
Vc = 2.41 v
Explanation:
voltage (v) = 16 v
find the voltage between the ends of the copper rods .
applying the voltage divider theorem
Vc = V x (
)
where
- Rc = resistance of copper =
(l = length , a = area, ρ = resistivity of copper)
- Ri = resistance of iron =
(l = length , a = area, ρ₀ = resistivity of copper)
Vc = V x (
)
Vc = V x (
)
Vc = V x (
)
where
- ρ = resistivity of copper = 1.72 x 10^{-8} ohm.meter
- ρ₀ = resistivity of iron = 9.71 x 10^{-8} ohm.meter
Vc = 16 x (
)
Vc = 2.41 v
1900 millimeters thats wht i got
