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Mademuasel [1]
4 years ago
8

Which scientific discovery commonly attributed to Newton did Hooke also claim to have played a major role in?

Physics
1 answer:
tia_tia [17]4 years ago
5 0

Answer:

laws of gravitation

Explanation:

my school has the same course as yours and i got it right

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Match the words in the left-hand column to the appropriate blank in the sentences in the right-hand column. use each word only o
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<span>1. About a trillion comets are thought to be located far, far beyond pluto in the Oort cloud. Oort cloud is theoretical cloud of predominantly icy planetesimals and. Many scientists have a belief that it surrounds the Sun at the distance of approximately between 50,000 and 200,000 AU. Such forces as  passing stars and of the Milky Way usually easily affect the outer Oort cloud and dislodge comets right from their orbits through the Oort the cloud and then they send them to the the inner Solar System.
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</span>

4. A comet's nucleus is the frozen portion of a comet. The conet nucleus is  the solid center of the head of a comet that is also called ''dirty snowball'' or an ''icy dirtball'' among astronomists. It consists of rock, dust, and frozen gases and when they are heated by the Sun they form a coma (which is an atmosphere that surrounds nucleus) by sublimating of the gases.


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6. The Kuiper Belt extends from about beyond the orbit of neptune to about twice the distance of neptune from the sun.  It is the circumstellar disc that uccurs in the Solar System beyond the already known planets. Its formreminds of asteroid belt, but it is far larger, to be more exact in 20 times. I

5 0
3 years ago
Calculate specific heat of liquid if a 450. g iron block is heated to 98.0 C and then droped into a calorimeter with 125 g of un
Naya [18.7K]

Answer:

Specific heat of liquid 1.258 \ J/g^0C.

Explanation:

We know in thermal equilibrium :

Loss in heat by iron block = Gain in heat by liquid .

Specific heat of iron = 0.45 J/g^0C.  { source internet }

Now , loss in heat by iron block = mC_{iron}\Delta T=450\times 0.45\times 57.6=11664\ J.

Heat gain by liquid=mC_{liquid}\Delta T=450\times C_{liquid}\times 20.6=9270\times C_{liquid}.

Equating both we get :

C_{liquid}=1.258 \ J/g^0C.

7 0
3 years ago
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