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Harman [31]
3 years ago
6

This is the answer fellas

Chemistry
1 answer:
lubasha [3.4K]3 years ago
5 0

Answer:

Thx man!

Explanation:

Brainliest Please!

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Can 1750 mL of water dissolve 4.6 moles of Copper Sulfate CuSO4? _________ Why? / Why not?
Wewaii [24]

Answer:

  • <u>No, you cannot dissolve 4.6 moles of copper sulfate, CuSO₄, in 1750mL of water.</u>

Explanation:

This question is part of a Post-Lab exercise sheet.

Such sheet include the saturation concentrations for several salts.

The saturation concentration of Copper Sulfate, CuSO₄, indicated in the table is 1.380M.

That means that 1.380 moles of copper sulfate is the maximum amount that can be dissolved in one liter of solution.

Find the molar concentration for 4.6 moles of copper sulfate in 1,750 mL of water.

You need to assume that the volume of water (1750mL) is the volume of the solution. This is, that the 4.6 moles of copper sulfate have a negligible volume.

<u>1. Volume in liters:</u>

  • V = 1,750 mL × 1 liter / 1,000 mL = 1.75 liter

<u />

<u>2. Molar concentration, molarity, M:</u>

  • M = number of moles of solute / volume of solution in liters

  • M = 4.6 moles / 1.75 liter = 2.6 M

Since the solution is saturated at 1.380M, you cannot reach the 2.6M concentration, meaning that you cannot dissolve 4.6 moles of copper sulfate, CuSO₄ in 1750mL of water.

8 0
3 years ago
Calculate the mass of magnesium needed to make 25g of magnesium oxide​
puteri [66]

Explanation:

here's the answer to your question about

6 0
3 years ago
A mixture of CO2 and Kr weighs 41.0 g and exerts a pressure of 0.729 atm in its container. Since Kr is expensive, you wish to re
Elena-2011 [213]

Answer:

a) 24.31 g

b) 16.69 g

Explanation:

A mixture of CO2 and Kr weighs 41.0 g and exerts a pressure of 0.729 atm in its container.

After the CO2 is completely removed by absorption with NaOH(s), the pressure in the container is 0.193 atm.

Therefore, Pressure of Kr = 0.193 atm

Pressure of CO2  = 0.729 - 0.193 = 0.536 atm

Their mole fraction can be also determined as follows:

CO2 = \frac{Presssure due to CO_2}{Total pressure}

CO2 = \frac{0.536}{0.729}

= 0.735

Also; for Kr ; we have

Kr = \frac{0.193}{0.729}

Kr = 0.265

Molar mass of CO2 = 44 g/mol

Molar mass of Kr = 83.78 g/mol

Mass of CO2 = mole fraction * molar mass = 0.735 * 44 = 32.34

Mass of Kr = 0.265 *  83.78 = 22.20

Total mass = 32.34 +22.20 = 54.54

The Percentage of gas in mixture is  as follows:

% CO2 = \frac{32.34}{54.54}* 100 %

= 0.5930

= 59.30%  

(a) Mass of CO2 in mixture = 0.5930* 41 g = 24.31 g

% Kr =\frac{22.20}{ 54.54} * 100 %

= 0.407

= 40.70 %

(b) Mass of Kr in mixture = 0.407 * 41 = 16.69 g

4 0
3 years ago
Plz help me with this question
miskamm [114]

Answer:

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5 0
3 years ago
How many moles of NaCi are equivalent to 15.6
kodGreya [7K]
The moles of NaCl would be 0.2669277996234607 cause one gram of NaCl is equal to 0.017110756386119273 moles
4 0
3 years ago
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