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Mandarinka [93]
4 years ago
9

What is a process that returns to its beginning and repeat it self in the same sequence

Physics
1 answer:
jasenka [17]4 years ago
7 0

Answer:

a sequence

Explanation: was that an option?, or was it not a multiple choice question ?

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Through what potential difference should electrons be accelerated so that their speed is 1.0 % of the speed of light when they h
omeli [17]

Answer:

Explanation:

Considering non - relativistic approach : ----

Speed of electron = 1 % of speed of light

= .01 x 3 x 10⁸ m /s

= 3 x 10⁶ m /s

Kinetic energy of electron = 1/2 m v²

= .5 x 9.1 x 10⁻³¹ x ( 3 x 10⁶ )²

= 40.95 x 10⁻¹⁹ J

Kinetic energy in electron comes from lose of electrical energy equal to

Ve where V is potential difference under which electron is accelerated and e is electronic charge .

V x e = kinetic energy of electron

V x 1.6 x 10⁻¹⁹ = 40.95 x 10⁻¹⁹

V = 25.6 Volt .

6 0
3 years ago
Do you divide mass by volume to get density
bogdanovich [222]
Density<span> is the </span>mass<span> of an object </span>divided<span> by its </span>volume<span>. So the answer would be Yes. Hope it helps! (:</span>
7 0
3 years ago
Convert the following:
Alika [10]

Explanation:

A) 1 kg = 1000g

2500kg = 2500000g

B 1 hour = 3600 sec

335 hour = 1206000sec

C 1day = 24 hours

1 hour = 3600 sec

24 hours = 86400sec

5 0
3 years ago
Read 2 more answers
Alicia is asked to calculate the change in momentum that occurs as she stops her bicycle. This is equivalent to the______ Applie
emmainna [20.7K]
It is the force applied to the bycicle
3 0
3 years ago
A wire with resistance R is connected to the terminals of a 6.0 V battery. What is the potential difference between the ends of
Bas_tet [7]

Answer:

Potential difference = 6.0 V

I for 1.0Ω = 6 A

I for 2.0Ω = 3 A

I for 3.0Ω = 2 A

Explanation:

Potential difference (ΔV) = Current (I) x Resistance (R)

The potential difference is constant and equals 6.0 V, hence;

I = ΔV/R

When R = 1.0, I =6/1 = 6 amperes

When R = 2.0, I = 6/2 = 3 amperes

When R = 3.0, I = 6/3 = 2 amperes

<em>The potential difference is 6.0 V and the current is 6, 3, and 2 amperes for a resistance of 1.0, 2.0 and 3.0Ω respectively.</em>

7 0
3 years ago
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