Plugging in for the Earth's mass and for G, we have 11.2 km/s for the escape velocity for an object launched from the Earth's surface. This is about 25,000 miles per hour
 
        
             
        
        
        
Answer:
i)-6.25m/s
ii)18 metres
iii)26.5 m/s or 95.4 km/hr
Explanation:
Firstly convert 90km/hr to m/s
90 × 1000/3600 = 25m/s
(i) Apply v^2 = u^2 + 2As...where v(0m/s) is the final speed and u(25m/s) is initial speed and also s is the distance moved through(50 metres)
 0 = (25)^2 + 2A(50)
0 = 625 + 100A....then moved the other value to one
-625 = 100A
Hence A = -6.25m/s^2(where the negative just tells us that its deceleration)
(ii) Firstly convert 54km/hr to m/s
 In which this is 54 × 1000/3600 = 15m/s
 then apply the same formula as that in (i)
 
 0 = (15)^2 + 2(-6.25)s
 -225 = -12.5s
 
 Hence the stopping distance = 18metres
(iii) Apply the same formula and always remember that the deceleration values is the same throughout this question
0 = u^2 + 2(-6.25)(56)
u^2 = 700
Hence the speed that the car was travelling at is the,square root of 700 = 26.5m/s
In km/hr....26.5 × 3600/1000 = 95.4 km/hr
 
 
        
             
        
        
        
The behavior of an ideal gas at constant temperature obeys Boyle's Law of
p*V = constant
where
p = pressure
V = volume.
Given:
State 1:  
  p₁ = 10⁵ N/m² (Pa)
  V₁ = 2 m³
State 2:
  V₂ = 1 m³
Therefore the pressure at state 2 is given by
p₂V₂ = p₁V₁
or
p₂ = (V₁/V₂) p₁
    = 2 x 10⁵ Pa
Answer: 2 x 10⁵ N/m² or 2 atm.
        
             
        
        
        
Answer:
Horizontal distance, R = vo2 sin(2x45)/g
v = 285 km/h = 79.17 m/s
R = 79.172 x 1/1.6
R = 3917 m
R = 3.9 km
 
        
             
        
        
        
Answer: The Porsche Wins. Arrives 19secs earlier before the Honda.
Explanation: The head start of 1secs corresponded with the difference in acceleration {3.5m/s² - 3m/s²}=0.5m/s²
Using the first equation of motion we obtain the velocity which correspond to this acceleration (0.5m/s²) and time of 1secs where initial velocity u = 0
V = u + at
V= 0 + at 
V = 0.5 * 1 = 0.5m/s
Now let find the velocity of each of the car.
If V. a
 0.5m/s 0.5m/s²
 ........m/s. 3.5m/s²
Velocity of porche Vp
 = (3.5/0.5) * 0.5 = 3.5 m/s
Also if. V. a
 0.5m/s. 0.5m/s²
 .....m/s. 3 m/s²
Velocity of Honda Vh 
= {3/0.5} * 0.5 = 3m/s
So let's find the time t taken by both cars to cover the distance of 400m
Recall, 
Velocity = distance/time
Time t = distance/velocity
For Porche, t = 400/3.5 =114.29secs
For Honda, t = 400/3 = 133.33secs
Looking critically, we noticed that Porche car took shorter time.
The difference In time is 
= (133.33 - 114.29)secs = 19.04secs