In what may be one of the most remarkable coincidences in
all of physical science, the tangential component of circular
motion points along the tangent to the circle at every point.
The object on a circular path is moving in that exact direction
at the instant when it is located at that point in the circle. The
centripetal force ... pointing toward the center of the circle ...
is the force that bends the path of the object away from a straight
line, toward the next point on the circle. If the centripetal force
were to suddenly disappear, the object would continue moving
from that point in a straight line, along the tangent and away from
the circle.
Answer:
18.1347 m/s
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
g = Acceleration due to gravity = 9.81 m/s² = a
Total height the ball falls is 2.4619+14.3 = 16.7619 m
The speed at which the stone reaches the ground is 18.1347 m/s
<span>The question is asking us to fill in the gap in: (gap) is a force of attraction that occurs between objects due to their mass.The correct answer is b. gravity. People don't know that gravity works both ways: both objects atract each. The reason why we're more attracted to Earth than Earth is pulled to us is that Earth has a much higher mass - the bigger the mass, the stronger the atraction</span>
Answer:
Explanation:
The formula that you are working with is F = m*a
Since mass is one part of the formula if you increase the mass, you are going to increase the force.
The second one is much more difficult to answer because it is basically incomplete. This is one way to interpret it. If you start at a certain speed and increase during a known time period then effectively you are defining acceleration which is "a" in the formula.
Without those modifications, there is no answer.
Answer:
The velocity of the truck after this elastic collision is 15.7 m/s
Explanation:
It is given that,
Mass of the car, 
Mass of the truck, 
Initial velocity of the car, 
Initial velocity of the truck, u₂ = 0
After the collision the velocity of the car is, v₁ = -11 m/s
Let v₂ is the velocity of the truck after this elastic collision. Using the conservation of momentum as :
So, the velocity of the truck after this elastic collision is 15.7 m/s. Hence, the correct option is (c).
