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3 years ago

Corrosion is the tendency of a metal to revert back to its natural state.

1 answer:

algol133 years ago

3 0

Corrosion is the irreversible damage or destruction of living tissue or material due to a chemical or electrochemical reaction.

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Hii guys!! ~ i've comeback again!! could you please help me with an assignment?? i have a couple of i know questions!! thank you

Nimfa-mama [501]

Answer:

Speed = 10.24 m/s.

Explanation:

<u>Given the following data;</u>

Distance = 100m

Time = 9.77

To find her speed;

Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.

Mathematically, speed is given by the equation;

$Speed = \frac{distance}{time}$

Substituting into the equation, we have;

$Speed = \frac{100}{9.77}$

<em>Speed = 10.24 meter per seconds. </em>

5 0

3 years ago

A cylindrical specimen of a nickel alloy having

tia_tia [17]

Answer:

L = 0.475 m = 475 mm = 18.7 inches

Explanation:

A cylindrical specimen of a nickel alloy having an elastic modulus of 207 GPa and an original diameter of 10.2 mm (0.40 in.) will experience only elastic deformation when a tensile load of 8900 N (2000 lb ) is applied. Compute the maximum length of the specimen before deformation if the maximum allowable elongation is 0.25 mm (0.010 in).

E = 207 GPa = 207*10⁹ Pa

D = 10.2 mm = 0.0102 m

P = 8900 N

ΔL = 0.25 mm = 2.5*10⁻⁴ m

L = ?

We can use the Equation of the Hooke's Law

ΔL = P*L / (A*E) ⇒ L = ΔL*A*E / P

⇒ L = (2.5*10⁻⁴ m)*(π*(0.0102 m)²*0.25)*(207*10⁹ Pa) / (8900 N)

⇒ L = 0.475 m = 475 mm = 18.7 inches

7 0

4 years ago

Compare an Earth year to a cosmic year

sweet-ann [11.9K]

Compared with an Earth year, a galactic year represents time on a grand scale but its not a consistent measurement across the galaxy

4 0

3 years ago

A proton moves with a speed of 1.17 105 m/s through Earth's magnetic field, which has a value of 50.0 µT at a particular locatio

vlabodo [156]

a) Southward you need to apply right hand rule. If you close your hand to the east, your thumb will indicate south.

b) Given the equation for Magnetic Force

$F= qVB$

Replacing

$F= (1.16*10^{-19})(1.17*10^5)(50*10^{-6})$

$F=9.36*10^{-19}$

c) Given the second Newton's Law by

$F_g = 1.67*10^{-27}*9.81$

$F_g = 1.64*10^{-26}$

Given the electric force by,

$F_e = 1.6*10^{-19}*1.5*10^2$

$F_e = 2.4*10^{-17}N$

$F=9.36*10^{-19}N$

7 0

3 years ago

If the car has the same initial velocity, and if the driver slams on the brakes at the same distance from the tree, then what wo

Elena L [17]

Answer: The question is incomplete or some details are missing. Here is the complete question ; (a) The driver of a car slams on the brakes when he sees a tree blocking the road. The car slows uniformly with acceleration of −5.55 m/s2 for 4.05 s, making straight skid marks 63.0 m long, all the way to the tree. With what speed (in m/s) does the car then strike the tree? m/s

(b) What If? If the car has the same initial velocity, and if the driver slams on the brakes at the same distance from the tree, then what would the acceleration need to be (in m/s2) so that the car narrowly avoids a collision? m/s2

a ) With what speed (in m/s) does the car then strike the tree? m/s = 4.3125m/s

b) then what would the acceleration need to be (in m/s2) so that the car narrowly avoids a collision? m/s2 = -5.696m/s2

Explanation:

The detailed steps and calculation is as shown in the attached file.

6 0

3 years ago