An object is pushed with a force of 400 N for 20 meters; what is the work done on the object? Solve using W=F*d
1 answer:
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Answer:
a
The height is
b
The horizontal distance is
Explanation:
From the question we are told that
The speed is
The angle is
The height of the cannon from the ground is h = 2 m
The distance of the net from the ground is k = 1 m
Generally the maximum height she reaches is mathematically represented as
=>
=>
Generally from kinematic equation
Here s is the displacement which is mathematically represented as
s = [-(h-k)]
=> s = -(2-1)
=> s = -1 m
There reason why s = -1 m is because upward motion canceled the downward motion remaining only the distance of the net from the ground which was covered during the first half but not covered during the second half
a = -g = -9.8
So
=>
using quadratic formula to solve the equation we have
Generally distance covered along the horizontal is
=>
=>