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Anestetic [448]
3 years ago
15

State three acids, bases, and Salts commonly used in therapeutic processes​

Chemistry
1 answer:
Delvig [45]3 years ago
3 0
Acetic acid, phosphoric acid, hydrochloric acid.

sodium bicarbonate, magnesium hydroxide, aluminum hydroxide

calcium carbonate, sodium bicarbonate, magnesium sulfate.
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1 Aluminum reacts with oxygen to produce aluminum oxide, what is the chemical equation?​
Roman55 [17]

Answer:  Aluminum reacts with oxygen to produce aluminum oxide as follows: 4Al + 3O2 → 2Al2O3 a.

Explanation: I really really <u>hope</u> that was <u>helpful.</u>

4 0
3 years ago
Can you give examples of carbon in our living environment?
sveticcg [70]
Wastes
Fuel
Smoke
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Toxic chemicals
5 0
3 years ago
Read 2 more answers
The anion formed from an oxygen atom is called a(n)
marta [7]
A. Oxygen ion
I am not sure but that's the right one I think. If I am wrong then I am sorry
6 0
4 years ago
Question 5
Dafna11 [192]

The mass percent of oxygen is 32.82%.

<h3>What is a noble gas?</h3>

A noble gas is member of group 18 in the periodic table. The members of this group are known not to be reactive and they do not easily form compounds. However, there have been few compounds of the members of group 18 that have been reported.

Let us now calculate the relative molecular mass of xenon tetraoxide.

Xe + 4 (O)

131 + 4(16) = 195

Given that the mass of oxygen in the compound is 64, the mass  percent of oxygen in xenon tetroxide is obtained from;

64/195 * 100/1

= 32.82%

Learn more about mass percent:brainly.com/question/5394922

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5 0
2 years ago
I need help with 1,2,3, and 4
Schach [20]

Answer:

  • Problem 1: 1.85atm
  • Problem 2: 110mL
  • Problem 3: 290 mL
  • Problem 4: 1.14 atm

Explanation:

Problem 1

<u>1. Data</u>

<u />

a) P₁ = 3.25atm

b) V₁ = 755mL

c) P₂ = ?

d) V₂ = 1325 mL

r) T = 65ºC

<u>2. Formula</u>

Since the temeperature is constant you can use Boyle's law for idial gases:

          PV=constant\\\\P_1V_1=P_2V_2

<u>3. Solution</u>

Solve, substitute and compute:

         P_1V_1=P_2V_2\\\\P_2=P_1V_1/V_2

        P_2=3.25atm\times755mL/1325mL=1.85atm

Problem 2

<u>1. Data</u>

<u />

a) V₁ = 125 mL

b) P₁ = 548mmHg

c) P₁ = 625mmHg

d) V₂ = ?

<u>2. Formula</u>

You assume that the temperature does not change, and then can use Boyl'es law again.

          P_1V_1=P_2V_2

<u>3. Solution</u>

This time, solve for V₂:

           P_1V_1=P_2V_2\\\\V_2=P_1V_1/P_2

Substitute and compute:

        V_2=548mmHg\times 125mL/625mmHg=109.6mL

You must round to 3 significant figures:

        V_2=110mL

Problem 3

<u>1. Data</u>

<u />

a) V₁ = 285mL

b) T₁ = 25ºC

c) V₂ = ?

d) T₂ = 35ºC

<u>2. Formula</u>

At constant pressure, Charle's law states that volume and temperature are inversely related:

         V/T=constant\\\\\\\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

The temperatures must be in absolute scale.

<u />

<u>3. Solution</u>

a) Convert the temperatures to kelvins:

  • T₁ = 25 + 273.15K = 298.15K

  • T₂ = 35 + 273.15K = 308.15K

b) Substitute in the formula, solve for V₂, and compute:

        \dfrac{V_1}{T_1`}=\dfrac{V_2}{T_2}\\\\\\\\\dfrac{285mL}{298.15K}=\dfrac{V_2}{308.15K}\\\\\\V_2=308.15K\times285mL/298.15K=294.6ml

You must round to two significant figures: 290 ml

Problem 4

<u>1. Data</u>

<u />

a) P = 865mmHg

b) Convert to atm

<u>2. Formula</u>

You must use a conversion factor.

  • 1 atm = 760 mmHg

Divide both sides by 760 mmHg

       \dfrac{1atm}{760mmHg}=\dfrac{760mmHg}{760mmHg}\\\\\\1=\dfrac{1atm}{760mmHg}

<u />

<u>3. Solution</u>

Multiply 865 mmHg by the conversion factor:

    865mmHg\times \dfrac{1atm}{760mmHg}=1.14atm\leftarrow answer

3 0
3 years ago
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