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mina [271]
3 years ago
6

WHATS THE ANSWER GIVING BRAINLIEST

Chemistry
1 answer:
soldier1979 [14.2K]3 years ago
7 0

Q: Which type of severe weather is related to high-pressure systems

A: A high pressure system is a whirling mass of cool, dry air that generally brings fair weather and light winds. When viewed from above, winds spiral out of a high-pressure center in a clockwise rotation in the Northern Hemisphere. These bring sunny skies. A high pressure system is represented as a big, blue H.

If you take this answer into consideration knowing the weathers, you will get your answer

You might be interested in
True or false the Chemical symbol is the number assigned to elements based on the number of protons in the atom
Bad White [126]
False because the Chemical symbol is the latin names for the elements. Hopes this help!
5 0
3 years ago
A drop of water from a special dropper is 3ml. How many liters is this this. A(30) B(0.3) C(0.03) D(0.003)
Damm [24]
1L= 1000ml

D) 3ml=0.003L
3 0
4 years ago
2.5 piece of lithium is dropped into a 500 g sample of water at 22.1 C.ten temperature of the water increases to 23.5 C. How muc
Dominik [7]

Answer:

2.6 kJ  

Explanation:

The formula for the amount of heat (q) absorbed by the water is

q = mCΔT

1. Calculate ΔT

ΔT = 23.5 °C - 22.1 °C = 1.4 °C

2. Calculate q

q₂ = mCΔT = 500 g × 4.184 J·°C⁻¹g⁻¹ × 1.4 °C = 2900 J = 2.9 kJ

3 0
4 years ago
What is the parent isotope when Cl-33 is formed during a beta decay?
zzz [600]

Answer:

33/16 S

Explanation:

In beta decay, the atomic number of the daughter nucleus increases by one unit while the mass of the daughter nucleus remains the same as that of the parent nucleus.

Hence, if we know that a beta decay has occurred, then the parent nucleus must have the same mass as its daughter nucleus but have an atomic number that is less than that of the daughter nucleus by only one unit, hence the answer above.

7 0
4 years ago
Determine the heat needed to warm 25.3 g of copper from 22 degrees celsius to 39 degrees celsius.
Serggg [28]

Answer:

The heat needed to warm 25.3 g of copper from 22°C to 39°C is 165.59 Joules.

Explanation:

Q=mc\Delta T

Where:

Q = heat absorbed  or heat lost

c = specific heat of substance

m = Mass of the substance

ΔT = change in temperature of the substance

We have mass of copper = m = 25.3 g

Specific heat of copper = c = 0.385 J/g°C

ΔT  = 39°C - 22°C = 17°C

Heat absorbed by the copper :

Q=25.3 g\times 0.385 J/g^oC\times 17^oC=165.59 J

The heat needed to warm 25.3 g of copper from 22°C to 39°C is 165.59 Joules.

5 0
4 years ago
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