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Nutka1998 [239]
3 years ago
15

In regard to the Compton scattering experiment with x-rays incident upon a carbon block, as the scattering angle becomes larger,

what happens to the magnitude of difference between the incident and scattered wavelengths
Physics
1 answer:
BartSMP [9]3 years ago
6 0

Answer:

Increases

Explanation:

In the Compton scattering experiment with x-rays,

The change in operation

\Delta \lambda = \frac{h}{m_oc} [1-cos\theta]

Now rest being constant, as \theta increases, cos\theta decreases

Hence, The change in wavelength will increase with the increase in \theta.

Hence, wavelength increases with an increase in the angle of scatttering.

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How am I supposed to solve this?
RSB [31]

Answer:

4.02 km/hr

Explanation:

5 km/hr = 1.39 m/s

The swimmer's speed relative to the ground must have the same direction as line AC.

The vertical component of the velocity is:

uᵧ = us cos 45

uᵧ = √2/2 us

The horizontal component of the velocity is:

uₓ = 1.39 − us sin 45

uₓ = 1.39 − √2/2 us

Writing a proportion:

uₓ / uᵧ = 121 / 159

(1.39 − √2/2 us) / (√2/2 us) = 121 / 159

Cross multiply and solve:

159 (1.39 − √2/2 us) = 121 (√2/2 us)

220.8 − 79.5√2 us = 60.5√2 us

220.8 = 140√2 us

us = 1.115

The swimmer's speed is 1.115 m/s, or 4.02 km/hr.

7 0
3 years ago
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Initial velocity 10 m/s accelerates at 5 m/s for 2 seconds whats the final velocity
stiks02 [169]

Answer:

<em>The final velocity is 20 m/s.</em>

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

Being a the constant acceleration, vo the initial speed, and t the time, the final speed can be calculated as follows:

v_f=v_o+at

The provided data is: vo=10 m/s, a=5\ m/s^2, t=2 s. The final velocity is:

v_f=10~m/s+5\ m/s^2\cdot 2\ s

v_f=20\ m/s

The final velocity is 20 m/s.

8 0
3 years ago
Which of the answer choices best describes the property of volume? the amount of space a substance's matter occupies the amount
vova2212 [387]

Answer:

amount of space occupied

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Communication with submerged submarines via radio waves is difficult because seawater is conductive and absorbselectromagnetic wa
FrozenT [24]

Answer:

D. 4000 km

Explanation:

f = Frequency of wave that is being transmitted = 76 Hz

\lambda = Wavelength of wave that is being transmitted

v = The velocity of electromagnetic waves through air = 3\times 10^8\ m/s

Velocity of a wave is given by

v=f\lambda\\\Rightarrow \lambda=\frac{v}{f}\\\Rightarrow \lambda=\frac{3\times 10^8}{76}\\\Rightarrow \lambda=3947368.42105\ m=3947.36842105 km\approx 4000\ km

Hence, the approximate wavelength of the waves is 4000 km

8 0
3 years ago
How is your guys day going?​
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Good i’m tired how about you
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