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Len [333]
2 years ago
10

Question 2/5

Chemistry
1 answer:
Olegator [25]2 years ago
7 0
B

A definite chemical composition means that all occurrences of that mineral have a chemical composition that varies within a specific limited range and the atoms that make up the mineral must occur in specific ratios.
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As a phase change occurs when energy is removed or added to a system, the temperature of the substance stays constant because
Rashid [163]

Answer:

energy is being used to make or break bonds between molecules

Explanation:

if correct please consider brainliest

5 0
2 years ago
Gasoline has a density of 0.749 g/ml. how many pounds does 19.2 gallons of gasoline weigh?
Svetradugi [14.3K]
A good first step is writing the amount in terms of ml. 

19.2 gallons = 72.68 L = 72680 ml

that would mean it weighs 0.749*720680g = 54437.32ml = 54.437 L

hope that helps :)
6 0
2 years ago
Read 2 more answers
Aspirin has a formula c9h8o4. what is the molar mass of aspirin? 1. 95 g 2. 220 g 3. 180 g 4. 325 g
Debora [2.8K]
Molar mass is the mass of 1 mol of substance.
Molar masses of compounds can be calculated by the sum of the products of molar masses of individual atoms by number of corresponding individual atoms.
Compound formula is C₉H₈O₄
the molar masses of the atoms making up the compound 
C - 12 g/mol x 9  C  = 108 
H - 1 g/mol x 8 H = 8 
O - 16 g/mol x 4 O = 64
therefore molar mass of aspirin = 108 + 8 + 64 = 180 g/mol
answer is 3.180 
5 0
2 years ago
How did humans and animals adapt/survive to hurricane Katrina? AND Give examples of organisms that could not adapt/survive? PLS
guajiro [1.7K]
Some organisms that could not survive where cats, dogs, birds, horses, fish, cows, every animal that was in hurricane Katrina was affected by it. Some of these animals were able to survive and others were rescued from near death.
Most of the animals could not adapt to this change because they are not used to this type of change. The water was too strong for the fish and when the water brought the fish into any water/sea animal there was also medal because the water in through peoples houses (pretty much the man-made stuff that's not meant for sea is killing the animals in the water). 
Any animal that was left behind was affected. The animals could not adapt to this change they have never experienced something that tragic before, how they survived? Well, the animals that survived was mainly because of there natural instinct, before an earthquake or anything hits there are many animals that can sense the storm coming before it even hits and in this situation, the animal could, wake up, run to owner, flee, run to higher ground, and if they cant sense it. They see whats going on around them and then they know something is wrong.
8 0
3 years ago
Read 2 more answers
A student isolated 7.2 g of 1-bromobutane reacting equimolar amounts of 1-butanol (10 ml) and NaBr (11.1 g) in the presence of s
Alla [95]

<u>Answer:</u> The percent yield of the 1-bromobutane is 48.65 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For NaBr:</u>

Given mass of NaBr = 11.1 g

Molar mass of NaBr = 103 g/mol

Putting values in equation 1, we get:

\text{Moles of NaBr}=\frac{11.1g}{103g/mol}=0.108mol

The chemical equation for the reaction of 1-butanol and NaBr is:

\text{1-butanol + NaBr}\rightarrow \text{1-bromobutane}

By Stoichiometry of the reaction

1 mole of NaBr produces 1 mole of 1-bromobutane

So, 0.108 moles of NaBr will produce = \frac{1}{1}\times 0.108=0.108 moles of 1-bromobutane

  • Now, calculating the mass of 1-bromobutane from equation 1, we get:

Molar mass of 1-bromobutane = 137 g/mol

Moles of 1-bromobutane = 0.108 moles

Putting values in equation 1, we get:

0.108mol=\frac{\text{Mass of 1-bromobutane}}{137g/mol}\\\\\text{Mass of 1-bromobutane}=(0.108mol\times 137g/mol)=14.80g

  • To calculate the percentage yield of 1-bromobutane, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of 1-bromobutane = 7.2 g

Theoretical yield of 1-bromobutane = 14.80 g

Putting values in above equation, we get:

\%\text{ yield of 1-bromobutane}=\frac{7.2g}{14.80g}\times 100\\\\\% \text{yield of 1-bromobutane}=48.65\%

Hence, the percent yield of the 1-bromobutane is 48.65 %

5 0
2 years ago
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