Answer:
correct option is a. 0.2 mA toward D
Explanation:
given data
B carries = 1.5 mA
C carries current = 1.3 mA
solution
we take positive direction of current going away from the point D
and negative direction of current coming towards point D
so we use here kirchoff's current law
that is
iA + iB + iC = 0 ......................1
iA + 1.5 + (-1.3) = 0
iA = - 0.2 mA
so that current in wire A is 0.2 mA towards point D
correct option is a. 0.2 mA toward D
Left. Use right hand rule. Have hand wide open. Thumb points in direction of current.(which makes right angle with your index finger) Four fingers in direction of magnetic field and your palm should point in the direction of the force
Answer:
0.67 m/s
Explanation:
Mass of car 1, m₁ = 5000 kg
Mass of car 2, m₂ = 10,000 kg
Initial speed of car 1, u₁ = 2 m/s
Final speed of car 2, u₂ = 0 (at rest)
We need to find the final velocity of both cars when inelastic collision occurs. The momentum will remain conserved in case of inelastic collision. Using the conservation of momentum. Let V is the final speed.
So, after the inelastic collision, they will move with a speed of 0.67 m/s.
Force applied = F = 628 N
<span>Acceleration = a m/s² </span>
<span>Newton's 2nd law of motion : F = Ma </span>
<span> a = F/M -------- (1) </span>
<span>New mass of the crate = M1 = 3.8M kg </span>
<span>New acceleration = a1 = F/M1 = F/(3.8 M) ----- (2) </span>
<span>a1/a = {F/(3.8M)}/(F/M) = 1/3.8 = 10/38 = 5/19 ------- Answer</span>
Explanation:
It is given that,
Delfino is pushing the box with a force of 10 N to the left. Aleida is pushing the box with a force of 15 N to the right.
Aleida is exerting more force. He is the more stronger individual.
Net force is given by :
F = -10+15
F = 5 N
So, the net force is 5 N and it is in right direction.
