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zhuklara [117]
3 years ago
6

4. How much water would be needed to dilute at 750 ml solution of 2.8M HCl to a 1.0 M solution?

Chemistry
1 answer:
Andreyy893 years ago
8 0
I’m not sure but i hope u figure it out
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In a redox reaction, reduction is defined by the:
jonny [76]

Answer:

C. Gain in electron(s) resulting in a decrease of oxidation number.

Explanation:

Redox reactions are reactions involving transfer of of electron between two species (reduction specie) and (oxidation species) and change resulting in change in oxidation number.

Reduction in terms of redox reaction is the specie that accepts electron(s) and gets "reduced" since its oxidation state has been reduced.

For example

Cl + e- → Cl⁻

The above reaction is an example of reduction reaction taking place in a redox reaction. We can see that Chlorine oxidation state was changed from (0) to (-1) state.

5 0
3 years ago
Select the correct answer from each drop-down menu.
earnstyle [38]

Answer:

The granite block transferred <u>4080 joules</u> of energy, and the mass of the water is <u>35.84 grams</u>.

Explanation:

The equation needed to answer both parts of the question is:

Q = mcΔT

In this equation,

-----> Q = energy/heat (J)

-----> m = mass (g)

-----> c = specific heat (J/g°C)

-----> ΔT = change in temperature (°C)

<u>Part #1:</u>

First, you need to find the energy transferred from granite block using the previous equation. You have been given the mass, specific heat, and change in temperature.

Q = ? J                            c = 0.795 J/g°C

m = 126.1 g                     ΔT = 92.6 °C - 51.9 °C = 40.7 °C

Q = mcΔT

Q = (126.1 g)(0.795 J/g°C)(40.7 )

Q = 4080

<u>Part #2:</u>

Secondly, using the energy calculated in Part #1, you need to calculate the mass of the water. You have calculated the energy transferred, and have been given the specific heat and change in temperature.

Q = 4080 J                     c = 4.186 J/g°C

m = ? g                            ΔT = 51.9 °C - 24.7 °C = 27.2 °C

Q = mcΔT

4080 J = m(4.186 J/g°C)(27.2 °C)

4080 J = m(113.8592)

35.84 = m

4 0
2 years ago
Which consumers live in the open ocean?
mel-nik [20]
<h2>Answer:</h2>

<u>The right option is B. swordfish, dolphins, and sharks </u>

<h2>Explanation:</h2>

Consumers have to feed on producers or other consumers to survive. They always prey to eat other animals or species of their own kind. They can also eat other species who interfere in their habitat. There are three types of consumers i.e primary, secondary and top predators. The top ones living off others in the sea which cause danger, one who puts to death other sea animals include swordfish, dolphins, and sharks.

3 0
4 years ago
Read 2 more answers
Corn plants and milkweed plants grow in the same area. Over several years, the milkweed plants have taken over the field and the
Katyanochek1 [597]

Answer:

This question is incomplete, the complete part of the question is as follows:

This best demonstrates which type of an interaction between the plants?

A. cooperation

B. parasitism

C. commensalism

D. competition

The answer is D

Explanation:

Organisms in their natural environment interact with one another in so many ways. The ways by which this interaction occurs are; competition, predation, commensalism etc.

Competition is the interaction between two organisms in which one or both organisms are harmed due to limited resources. Competition occurs when the organisms involved occupy the same niche or utilize the same limited resources.

In this question involving corn plants and milkweed plants. They are said to grow in the same area. Over several years, the milkweed plants have taken over the field and the corn plants no longer have space to grow. In this case, there is a limited space for growth, hence, the corn plant and milkweed COMPETE.

8 0
3 years ago
The mathematical relationship between gas solubility and pressure is called Henry's Law, solubility = kHPgas where kH is the Hen
Diano4ka-milaya [45]

Answer : The unit of k_H in mol/L.mm Hg is, 1.8\times 10^{-6}mol/L.mmHg

Explanation :

As we know that the k_H is the Henry's Law constant for argon at 25^oC is, 1.4\times 10^{-3}mol/L.atm

Now we have to determine the unit of k_H in mol/L.mm Hg

Conversion used for pressure from atm to mmHg is:

1 atm = 760 mmHg

So,

k_H=1.4\times 10^{-3}mol/L.atm\times \frac{1atm}{760mmHg}

k_H=1.8\times 10^{-6}mol/L.mmHg

Thus, the unit of k_H in mol/L.mm Hg is, 1.8\times 10^{-6}mol/L.mmHg

5 0
3 years ago
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