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serg [7]
1 year ago
7

A basketball is thrown with an initial upward velocity of feet per second from a height of feet above the ground. the equation m

odels the height in feet t seconds after the basketball is thrown. after the ball passes its maximum height, it comes down and then goes into the hoop at a height of feet above the ground. about how long after it was thrown does it go into the hoop?
Physics
1 answer:
Ann [662]1 year ago
6 0

The answer is t=1.29 seconds.

<h3>What is Velocity?</h3>
  • The rapidity of movement or operation; swiftness; speed: a high wind velocity. Mechanics. the time rate of evolution of position of a body in a specified demand. the rate of speed with which something happens; rapidity of movement or reaction.
  • Velocity is the prime hand of the position as well as the rapidity of the object. It can be characterized as the distance covered by an object in a unit of time. Velocity can be defined as the displacement of an object in a unit of time.
  • Velocity (v) is a vector amount that measures displacement (or change in position, Δs) over the change in time (Δt), described by the equation v = Δs/Δt. Speed (or rate, r) is a scalar amount that measures the distance traveled (d) over the transformation in time (Δt), represented by the equation r = d/Δt.

To learn  more about Velocity, refer to:

brainly.com/question/4931057

#SPJ4

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a spiral spring of natural length 10.0cm has a scale pan hanging freely in its tower ends . When an object of mass of 20g is pla
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Answer:

Explanation:

There seems to be a typo in the problem statement.  It says the spring stretches to a shorter length after more mass is added.  Please check the problem statement.  I'm going to do the calculations assuming that the first length should be 11.80 cm and the second length should be 12.05 cm.

Hooke's law states that the force needed to compress or extend a linear spring is:

F = kΔx, where k is the stiffness and Δx is the displacement.

When a 20g object is placed in the pan, the spring stretches to a length of 11.80 cm.  The force of the spring is counteracting the weight of both the pan and the object. Therefore:

(m + 0.020) g = k (0.1180 - 0.100)

And when another 30g object is placed in the pan, the spring stretches to a length of 12.05 cm.

(m + 0.020 + 0.030) g = k (0.1205 - 0.100)

We now have two equations and two variables.  If we divide the second equation by the first equation:

(m + 0.050) / (m + 0.020) = (0.1205 - 0.100) / (0.1180 - 0.100)

(m + 0.050) / (m + 0.020) = 0.02050 / 0.0180

0.0180 (m + 0.050) = 0.02050 (m + 0.020)

0.0180 m + 0.0009 = 0.02050 m + 0.00041

0.00049 = 0.0025 m

m = 0.196

The pan has a mass of 0.196 kg, or 196 g.

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