Answer:
hypochlorite ion
Explanation:
The hypochlorous acid, HClO, is a weak acid with Ka = 1.36x10⁻³, when this acid is in solution with its conjugate base, ClO⁻ (From sodium hypochlorite, NaClO) a buffer is produced. When a strong acid as HCl is added, the reaction that occurs is:
HCl + ClO⁻ → HClO + Cl⁻.
Where more hypochlorous acid is produced.
That means, the HCl reacts with the hypochlorite ion present in solution
Answer is: the approximate freezing point of a 0.10 m NaCl solution is -2x°C.
V<span>an't
Hoff factor (i) for NaCl solution is approximately 2.
</span>Van't Hoff factor (i) for glucose solution is 1.<span>
Change in freezing point from pure solvent to
solution: ΔT = i · Kf · m.
Kf - molal freezing-point depression constant for water is 1,86°C/m.
m - molality, moles of solute per
kilogram of solvent.
</span>Kf and molality for this two solutions are the same, but Van't Hoff factor for sodium chloride is twice bigger, so freezing point is twice bigger.
Answer:
160.000 años corresponde a 16.000 décadas.
Explanation:
Para resolver correctamente el ejercicio debemos plantear la regla de tres simple de la siguiente manera:
1 década equivale a 10 años; A cuantas decadas equivalen 160.000 años?
1 década→10 años
x ←160.000 años
Debemos multiplicar 160.000 por 1 y luego dividir entre 10 ;
x=(
)=16.000 décadas; en notación científica sería 16x10^3.
Respuesta: 160.000 años corresponde a 16.000 décadas.
Given :
Measurements
.
To Find :
The multiplication using significant figures .
Solution :
We know , the least number of significant figures in any number of the problem determines the number of significant figures in the answer.
So , significant figure( S.F) in 4.5 cm is 2 .
S.F in 2000.0 cm is 5 .
S.F in 4 cm is 1 .
So , minimum S.F is 1 .
Therefore , S.F of their product is 1 .
Now , multiplying them we will get :

Now , converting 36000 in 1 significant digit .
First we will write it in exponential 2 S.F form.

Now , to convert 3.6 into 1 S.F we should round off this .
So , round off 3.6 we will get 4 .
Therefore , The multiplication using significant figures is
.
Hence , this is the required solution .