A i believe is the answer
<span>Both are composed of two elements (that means binary).
Ionic is composed of two ions, metallic cation-positive ions, and nonmetallic anion - negative ions. For example NaCl (sodium-chloride).
Molecular compounds are composed of two nonmetallic elements. For example HCl (hydrochloric acid).</span>
Answer:
Explanation:
From the given study,
the molecular formula of the given aromatic compound = C9H12
the first process we suppose to carry out is to calculate the double bond equivalence.
So, the double bond equivalence 
DBE = 4
Hence, the aromatic compound possesses 4 double bonds, this signifies that the might be a presence of benzene ring.
The substitutional products of the aromatic hydrocarbon C9H12 can be seen in the attached file below.
Answer:
See explanation
Explanation:
From the analysis we have in the question, we must look towards a first row transition metal ion having a d^6 configuration because it yields a paramagnetic complex having four unpaired electrons and a diamagnetic complex having no unpaired electrons.
We have two possible candidates in mind, Fe^2+ and Co^3+. However, Fe^2+ does not form as many coloured complexes as stated in the question so we have to eliminate that option.
We are now left with only Co^3+. Various ligands are going to cause these various colours of Co^3+ to appear in solution.
Hence, we can deduce from all these that the nature of ligands determines the colour of the complex . Don't forget that the colour of a complex arises from crystal field splitting.
What context are you asking it in?
The answer could be the electromagnetic interaction if you're talking about the 4 fundamental interactions, or ionic interaction, or electrostatic interaction.
