Answer:
C).
Explanation:
Because the organs in our body helps us to function.
Answer:
1.4% salt residue
Explanation:
Mass percent can be found using the formula:
mass of solute (grams)
------------------------------------ x 100%
mass of solution (grams)
Therefore, since you have been given the weights of both the solute and solution, you can use the formula to solve for the mass percent.
3.50 g salt residue
----------------------------- = 0.014 x 100% = 1.4% salt residue
250 g salt solution
The chemical nature of Q sepharose which allows it to be used as an ion exchanger include the following: It is an insoluble matrix which is in form of micro beads. The bead are porous, which provides a large surface area within and outside them. This properties make it possible for Q sepharose to finely separate different organic molecules.<span />
383.5 grams is the mass of water should be added to 22.0 g of KCl to make a 5.50 % by mass solution.
Explanation:
Given that:
Solution to be prepared is 5.5 %
mass of KCl is 22 gram
mass of water required =?
5.5 % solution means that
5.5 grams in 100 ml or gram of water to make solution.
let the water required is 5.5 + x, so the equation will be
5.5 =
x 100
121+ 5.5x = 2200
5.5 x = 2200-121
x = 
x = 378 grams
The mass of water added to KCl to make it 5.5% percent solution is
5.5 +378
= 383.5 grams.
to make the solution of 5.5 percent of KCl weighing 22 grams.
To determine the heat required in order to decompose a certain amount of a substance, we need information on the heat needed to decompose one mole of the substance. This value are readily available online and other sources. For this reaction, the heat needed is 129 kJ per 2 mol of NaHCO3. We calculate as follows:
129 KJ / 2 mol NaHCO3 (1 mol / 84.01 g ) (25.5 g NaHCO3 ) = 19.58 kJ of heat is needed.
