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Zinaida [17]
3 years ago
7

No caso da pessoa ser um atleta profissional,essa demanda de energia pode subir até 5400Kcal. Transforme essa medida de energia

nas unidades de caln Joule (J) e em (KJ), Com a conta.
Chemistry
1 answer:
ddd [48]3 years ago
6 0

Answer:

If you speak Any English i Think I will be able to help you Los Amigo

Explanation:

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Which of the following are products of the reaction listed? Zn + 2HCI
Alexus [3.1K]

Answer:

uh A.)? [ZnCI2+H2]? /////////

5 0
3 years ago
There are only two isotopes of gallium: ^69Ga (68.926 amu) and ^71Ga(70.025 amu). The average atomic mass of gallium is 69.723 a
SVEN [57.7K]
The question ask for the percentage of the abundance of galium-69 where there is two isotopes of galium: the 69Ga and the 71Ga. The average atomic mass of gallium is 69.723 amu. So the formula would be <span>69.723amu=(%x)∗(68.926amu)+(1−%x)∗(70.025amu) and the answer to this is 1.58%</span>
3 0
3 years ago
Calculate the mass of grams of 14.79ml of a substance. It'd density is 1.193gml
Alisiya [41]
<span>D=m/v

Given:
d=1.193g/ml
v= 14.79ml

Solution
m=dv
m=1.193g/ml x 14.79ml

m= 17.644g

Density is the mass per volume of the material. Basically, it refers to the measurement of how crammed together is the matter. The formula to calculate density is rho = m/v wherein rho is the density, m stands for the mass and v stands for the volume.</span>
8 0
3 years ago
A volume of 125 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If
VMariaS [17]

Answer:

41.9 g

Explanation:

We can calculate the heat released by the water and the heat absorbed by the steel rod using the following expression.

Q = c × m × ΔT

where,

c: specific heat capacity

m: mass

ΔT: change in temperature

If we consider the density of water is 1.00 g/mol, the mass of water is 125 g.

According to the law of conservation of energy, the sum of the heat released by the water (Qw) and the heat absorbed by the steel (Qs) is zero.

Qw + Qs = 0

Qw = -Qs

cw × mw × ΔTw = -cs × ms × ΔTs

(4.18 J/g.°C) × 125 g × (21.30°C-22.00°C) = -(0.452J/g.°C) × ms × (21.30°C-2.00°C)

ms = 41.9 g

3 0
3 years ago
How many grams are in 5.2 grams of K
AleksAgata [21]
I think you meant K as in kilograms?
If so, the answer should be 0.0052.
4 0
3 years ago
Read 2 more answers
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