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hichkok12 [17]
3 years ago
8

What is a core self-evaluation, include identifying and explaining the components of core self-evaluation. And, how a group lead

er can use CSEs to create a more effective unit
Engineering
2 answers:
Brilliant_brown [7]3 years ago
8 0

Answer and Explanation:

Core self-evaluations (CSEs) stands for a wide personality trait that comprises of 4 positive individual traits, namely:

(1) self-efficacy

(2) self esteem

(3) locus of control

(4) emotional stability.

Baiscally, when people have a positive evaluation about themselves, or quality core self-evaluation, they believe that they are worthy and fit for a task. They trust their capability and effectiveness. This leads to some implications in their managers duties and careers, which could either be positive or negative.

A group leader can use CSEs to create a more effective unit by implementing the ten items points of Generalized Self Efficacy Tool to test the self efficiency of individual personnels in that unit.

Fudgin [204]3 years ago
6 0

Answer: Core self evaluation CSE is a way we assess our lives and attitude to our environment including people around us and our work.

Explanation:

The key components of Core self evaluation are:

Self-efficacy: is the ability to be effective in different situations or how robust we are in coping with unfamiliar situations.

Self-esteem: is a positive belief in oneself, in one’s abilities and expectations of ourselves.

Locus of control: this is how much control we feel we have over what happens to us or what we do. People who feel more in control of the events that happen to them have a more positive and proactive attitude than those who do not.

Emotional stability/Neuroticism: Emotional stability is the ability to control negative emotions. Mood swings and anxiety are signs of low emotional stability or high neuroticism.  

A leader can use CSEs to build a more effective unit by identifying the key components each team member has, lacks or can improve on. Individuals who have high self efficacy, self esteem, locus of control and emotional stability are productive, positive and valuable team members. The leader can encourage each person to improve on their weak points as it is in the interest of the team.  

Also, the leader can assign tasks that use the strength of each person. For example, the most emotional stable team member can be in charge of crisis management.

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2 years ago
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This problem demonstrates aliasing. Generate a 512-point waveform consisting of 2 sinusoids at 200 and 400-Hz. Assume a sampling
aalyn [17]

Answer and Explanation:

clear all; close all;  

N=512;  

t=(1:N)/N;

fs=1000;  

f=(1:N)*fs/N;

x= sin(2*pi*200*t) + sin(2*pi*400*t);  

y= sin(2*pi*200*t) + sin(2*pi*900*t);

for n = 1:20  

a(n) = (2/N)*sum(x.*(cos(2*pi*n*t)))

b(n) = (2/N)*sum(x.*(sin(2*pi*n*t)))  

c(n) = sqrt(a(n).^2+b(n).^2)  

theta(n) =-(360/(2*pi))*atan(b(n)./a(n));  

end  

plot(f(1:20),c(1:20),'rd');

disp([a(1:4),b(1:4),c(1:4),theta(1:4)])

8 0
3 years ago
A ball thrown vertically upward from the top of a building of 60ft with an initial velocity of vA=35 ft/s. Determine (a) how hig
Masteriza [31]

Answer:

A.) 62.5 ft

B.) 3.58 seconds

C.) 8.58 seconds

Explanation:

A.) Given that a ball is thrown vertically upward from the top of a building of 60ft with an initial velocity of vA=35 ft/s

To determine how high above the top of the building the ball will go before it stops at B, let us use the third equation of motion.

V^2 = U^2 - 2gH

Since the ball is going up, g will be negative. And at maximum height, V = 0

Substitute all the parameters into the formula

0 = 35^2 - 2 × 9.8 × H

19.6H = 1225

H = 1225/19.6

H = 62.5 ft

(B) The time tAB it takes to reach its maximum height will be achieved by using second equation of motion

H = Ut - 1/2gt^2

Substitutes all the parameters into the formula

62.5 = 35t - 1/2 × 9.8 × t^2

62.5 = 35t - 4.9t^2

4.9t^2 - 35t + 62.5 = 0

Let's use quadratic equations to find t

Divide all by 4.9

t^2 - 7.143t + 12.755 = 0

t^2 - 7.143t + 3.57^2 = - 12.755 + 3.57^2

( t - 3.57)^2 = 0.000102

( t - 3.57 ) = +/-( 0.01 )

t = 3.57 + 0.01

t = 3.58 seconds

Ignore the negative one.

(C) the total time tAC needed for it to reach the ground at C from the instant it is released.

When the object is falling back from B, the initial velocity = 0. And the height h will be 60 + 62.5 = 122.5 ft

Using equation 2 of equations of motion again.

h = 1/2gt^2

122.5 = 1/2 × 9.8 × t^2

122.5 = 4.9t^2

t^2 = 122.5/4.9

t^2 = 25

t = 5

Total time = 5 + 3.58 = 8.58 seconds

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3 years ago
Given a two-dimensional steady inviscid air flow field with no body forces described by the velocity field given below. Assuming
kolbaska11 [484]

Answer:

the pressure gradient in the x direction = -15.48Pa/m

Explanation:

  • The concept of partial differentiation was used in the determination of the expression for u and v.
  • each is partially differentiated with respect to x and the appropriate substitution was done to get the value of the pressure gradient as shown in the attached file.

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madreJ [45]

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