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sasho [114]
3 years ago
15

Debbie was doing a science lab, and she was instructed to decide whether a piece of plastic would float or sink without actually

putting the plastic in the water. How could she do this?
Chemistry
2 answers:
Mandarinka [93]3 years ago
8 0
Find the density of the plastic. if the density is less than that of water, it's going to float. If it's more than the density of water, then it's going to sink.
Zinaida [17]3 years ago
8 0
You have to find the density
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A gas has a volume of 45.0 mL and a pressure of .98 atm. If the pressure increased to 2.1 atm and the temperature remained the s
goblinko [34]

Answer: The new volume is 95.45 mL.

Explanation:

Given: V_{1} = 45.0 mL,         P_{1} = 0.98 atm

P_{2} = 2.1 atm,               V_{2} = ?

According to Boyle's law, at constant temperature the pressure of a gas is inversely proportional to its volume.

Therefore, formula used to calculate the new volume is as follows.

\frac{P_{1}}{V_{1}} = \frac{P_{2}}{V_{2}}

Substitute the values into above formula as follows.

\frac{P_{1}}{V_{1}} = \frac{P_{2}}{V_{2}}\\\frac{0.98 atm}{45.0 mL} = \frac{2.1 atm}{V_{2}}\\V_{2} = 95.45 mL

Thus, we can conclude that the new volume is 95.45 mL.

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3 years ago
In the reaction 3H2+ ____ N2 --> 2 NH3, what coefficient should be placed in front of N2 to balance the reaction?
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A.) 1 is your answer.......
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Question 20 of 25
Mnenie [13.5K]

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I think that electonegativity increases

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Answer:None of the tunes make a correct statement the third choice is closed but may still dating the pencil operates broken because the light been to a zoo from a straight line when it across the boundary between air and water

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5 0
3 years ago
The enthalpy of fusion of H2O (s) at its normal melting point is 6.01 kJ/mol. What is the entropy change for freezing 1 mole of
Rom4ik [11]

Answer:

22.01J/Kmol

Explanation:

The parameters given in this question are;

Enthalpy (H) = 6.01 kJ/mol.

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The formular relationship between entropy and enthalpy is given as;

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Temperature for water at freezing point = 0C + 273 = 273 K (converting to Kelvin)

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