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Soloha48 [4]
2 years ago
11

) An organic chemistry lab book gives the following solubility data for oxalic acid 9.5g/100ml water 23.7g/100ml ethanol 16.9g/1

00ml ether (a) A 14CL student has 40 g of oxalic acid in 1000ml of water and wishes to extracted into an organic solvent for further experiments. Which solvent should the student use for the extraction
Chemistry
1 answer:
mart [117]2 years ago
5 0

Answer:

Ethanol

Explanation:

Solvent extraction is the process in which a compound transfers from one solvent to another owing to the difference in solubility or distribution coefficient between these two solvents(Science Direct).

We have to remember that oxalic acid will be extracted better into a solvent in which it is more soluble. From the data given; oxalic acid is more soluble in ethanol than in ether.

This simply means that ethanol is a better solvent for extracting oxalic acid  from water when compared to ether.

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Compare and contrast how observations and results can be used to
worty [1.4K]

Answer:

by statistical analyses, especially by determining the p-value

Explanation:

In general, observations and results obtained from experimental procedures are subjected to a statistical test to check the robustness of the working hypothesis. The p-value is the most widely used statistical index in order to test such observations and results. The p-value is the statistical probability of obtaining extreme observed results when the null hypothesis is considered correct. A p-value lesser than 0.05 generally is considered statistically significant and then the null hypothesis can be rejected. In consequence, a very low p-value (which is obtained by statistical analysis of the observations and results), indicates that there is strong evidence in support of the alternative hypothesis.

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3 years ago
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Anarel [89]
D. container four because of the water
3 0
2 years ago
What is the volume of 40g of sugar given it’s listed density
lora16 [44]

Answer:

25.157 cm³

Explanation:

Data Given:

Mass of Sugar (m) = 40g

Density of sugar given in literature = 1.59 g/cm³

Volume of Sugar = ?

The formula will be used is

                              d = m/v ........................................... (1)

where

D is density

m is the mass

v is the volume

So

Rearrange the Equation (1)

                              d x v = m

                               v = m/ d         ................................................ (2)

put the given values in Equation  (2)

                       v = 40g / 1.59 g/cm³

                       v = 25.157 cm³

volume of 40 g of sugar = 25.157 cm³

8 0
3 years ago
You have a 15.0 gram sample of gold at 20.0°C. How much heat does it take to raise the temperature to 100.0°C?
Nadusha1986 [10]

Answer:

=154.8 J

Explanation:

The rise in temperature is contributed by the change in temperature.

Change in enthalpy = MC∅,  where M is the mass of the substance, C is the specific heat capacity and ∅ is the change in temperature.

Change in temperature = 100.0°C-20.0°C=80°C

ΔH=MC∅

The specific heat capacity of gold= 0.129 J/g°C

ΔH= 15.0g×0.129J/g°C×80°C

=154.8 J

7 0
3 years ago
How many TOTAL atoms are in the following molecule? NaHCO3
blagie [28]

Answer:

NaHCO3 = No. of atoms are 1 sodium + 1 Hydrogen + 1 carbon + 3 oxygens = 6 atoms per molecule.

6 0
3 years ago
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