A chemical change or relation
Explanation:
(a) Molar mass of is 691.92 g/mol. And, there is 0.76 g of sodium monofluorophosphate () in 100 ml.
Molar mass of fluorine is 19 g/mol.
This means that in 691.92 g/mol there are 19 g/mol of fluorine is present. Hence, mass of fluorine present in 0.76 g is calculated as follows.
Mass of fluorine =
= 0.021 g
As, 1 g = 1000 mg. Hence, 0.021 g = 21 mg.
Therefore, mass of florine atoms in present was 21 mg.
(b) As we know that number of moles equal mass divided by molar mass.
Therefore, No. of moles of fluorine =
=
= 0.001 mol
Hence, according to mole concept in one mole there are atoms.
So, in 0.001 mole number of fluorine atoms will be calculated as follows.
atoms.
= atoms
Therefore, there are atoms of fluorine were present.
(4.50x10^16)/(6.02x10^24) = 7.5mols
7.5mols x 39.1= 293.25grams