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S_A_V [24]
3 years ago
6

Please help me fast

Physics
1 answer:
MakcuM [25]3 years ago
6 0

Answer:

b I think. sorry if it's wrong

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If We Start With 48 Atoms Of A Radioactive Substance, How Many Would Remain After One Half-life?
balu736 [363]

<span>One half-life produces (1/2) of the decaying substance.

There would still be  48  atoms.  But  24  would have thrown off
particles from their nucleuses, and only  24  would still be radioactive.</span>

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4 years ago
A statue is made of bronze, which is an alloy of about 80% copper and 20% tin. Which metal is in the higher concentration in thi
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The answer is B because it's 80 percent copper, that's a greater number then 20.
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Which number is not found on the periodic table​
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3 years ago
A physical pendulum in the form of a planar object moves in simple harmonic motion with a frequency of 0.680 Hz. The pendulum ha
sineoko [7]

Answer:

Therefore, the moment of inertia is:

I=0.37 \: kgm^{2}

Explanation:

The period of an oscillation equation of a solid pendulum is given by:

T=2\pi \sqrt{\frac{I}{Mgd}} (1)

Where:

  • I is the moment of inertia
  • M is the mass of the pendulum
  • d is the distance from the center of mass to the pivot
  • g is the gravity

Let's solve the equation (1) for I

T=2\pi \sqrt{\frac{I}{Mgd}}

I=Mgd(\frac{T}{2\pi})^{2}

Before find I, we need to remember that

T = \frac{1}{f}=\frac{1}{0.680}=1.47\: s

Now, the moment of inertia will be:

I=2*9.81*0.340(\frac{1.47}{2\pi})^{2}  

Therefore, the moment of inertia is:

I=0.37 \: kgm^{2}

I hope it helps you!

7 0
3 years ago
A satellite is in a circular orbit around an unknown planet. The satellite has a speed of 1.75 104 m/s, and the radius of the or
Arisa [49]

Answer:

v = 1.32 10² m

Explanation:

In this case we are going to use the universal gravitation equation and Newton's second law

    F = G m M / r²

    F = m a

In this case the acceleration is centripetal

    a = v² / r

The force is given by the gravitational force

    G m M / r² = m v² / r

    G  M/r =  v²

Let's calculate the mass of the planet

    M = v² r / G

    M = (1.75 10⁴)² 5.00 10⁶ / 6.67 10⁻¹¹

    M = 2.30 10²¹ kg

With this die we clear the equation to find the orbit of the second satellite

    v = √ G M / r

    v = √ (6.67 10⁻¹¹ 2.30 10²¹ / 8.75 10⁶)

    v = 1.32 10² m

8 0
3 years ago
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