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malfutka [58]
3 years ago
12

Ayuda con este crucigrama

Physics
1 answer:
Viktor [21]3 years ago
3 0

Answer:

no abla espenol udiejeir

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Suppose a clay model of a koala bear has a mass of 0.205 kg and slides on ice at a speed of 0.720 m/s. It runs into another clay
Westkost [7]

Answer:

Final velocity, v = 0.28 m/s

Explanation:

Given that,

Mass of the model, m_1=0.205\ kg

Speed of the model, u_1=0.72\ m/s

Mass of another model, m_2=0.32\ kg

Initial speed of another model, u_2=0

To find,

Final velocity

Solution,

Let V is the final velocity. As both being soft clay, they naturally stick together. It is a case of inelastic collision. Using the conservation of linear momentum to find it as :

m_1u_1+m_2u_2=(m_1+m_2)V

V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}

V=\dfrac{0.205\times 0.72+0.32\times 0}{(0.205+0.32)}

V = 0.28 m/s

So, their final velocity is 0.28 m/s. Hence, this is the required solution.

6 0
3 years ago
What is light pollution?
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Light pollution<span> is excessive and inappropriate artificial </span>light<span>. The four components of </span>light pollution<span> are often combined and may overlap: Urban Sky Glow—the brightening of the night sky over inhabited areas. </span>LightTrespass—light<span> falling where it is not intended, wanted, or needed.</span>
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The rate at which correct flows is measured in _?
Reika [66]

C. amperes

this what i think it is

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3 years ago
The attractive force that acts between all objects is the (5 points)
Talja [164]
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3 years ago
You pull your little sister across a flat snowy field on a sled. Your sister plus the sled have a mass of 25 kg. The rope is at
erik [133]

Answer

Work done will be equal to 1229.296 J

Explanation:

We have given mass of the sister m = 25 kg

Angle between rope and ground \Theta =38^{\circ}

Force F = 30 N  

So horizontal force =Fcos\Theta =30\times cos38^{\circ}=23.64N

Distance traveled d = 52 m

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Work done is equal to multiplication of horizontal force and distance

So work done W=23.64\times 52=1229.296J

7 0
3 years ago
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