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makkiz [27]
3 years ago
13

A car is stationary. It accelerates at 0.8 ms^2

Physics
1 answer:
lara31 [8.8K]3 years ago
8 0

Answer:

the car’s final displacement is 60 m

Explanation:

Given;

initail velocity of the car, u = 0

acceleration of the car, a = 0.8 m/s²

time of motion, t = 10 s

The first displacement of the car:

x_1 = ut + \frac{1}{2} at^2\\\\x_1 = 0 + \frac{1}{2} (0.8)(10)^2\\\\x_1 = 40 \ m

The second displacement of the car;

acceleration, a = 0.4 m/s²,   time of motion, t = 10 s

x_2 = ut + \frac{1}{2} at^2\\\\x_2 = 0 + \frac{1}{2} (0.4)(10)^2\\\\x_2 = 20 \ m

The final displacement of the car;

x = x₁  +  x₂

x = 40 m  +  20 m

x = 60 m

Therefore, the car’s final displacement is 60 m

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Answer:

a) a=5.7551 \times g

b) d=20.5539\times g

Explanation:

Given:

  • speed of rocket initially, v_i=0\ m.s^{-1}
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Now as a fraction of gravity:

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4 years ago
A comet is in an elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4.6 multiply 1010 m (inside t
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We will apply the concepts related to energy conservation to develop this problem. In this way we will consider the distances and the given speed to calculate the final speed on the path from the sun. Assuming that the values exposed when saying 'multiply' is scientific notation we have the following,

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