Answer:
3.8 g/mL
Explanation:
From the question given above, the following data were obtained:
Volume of Water = 60 mL
Volume of Water + Object = 73.5 mL
Mass of object = 51.3 g
Density of object =?
Next, we shall determine the volume of the object. This can be obtained as follow:
Volume of Water = 60 mL
Volume of Water + Object = 73.5 mL
Volume of object =?
Volume of object = (Volume of Water + Object) – (Volume of Water)
Volume of object = 73.5 – 60
Volume of object = 13.5 mL
Finally, we shall determine the density of the object as illustrated below:
Volume of object = 13.5 mL
Mass of object = 51.3 g
Density of object =?
Density = mass /volume
Density of object = 51.3 /13.5
Density of object = 3.8 g/mL
Thus, the density of the object is 3.8 g/mL
Answer
Na OH reacts with H Cl and forms Na Cl and H₂O
NaOH + HCl → NaCl + H₂O
Here we can see that 1 mole of NaOH reacting with 1 mole of HCl and forming 1 mole of NaCl and 1 mole of H₂O
when NaOH and HCl are added together in equal amount then they will completely neutralize each other but NaOH is hygroscopic in nature which means it can absorb water from air so it will not be weighted accurately.
hence, for neutralization we will take extra NaOH.
Answer:
336.6 grams of CO₂ and 183.6 grams of H₂O are formed from 2.55 moles of propane.
Explanation:
In this case, the balanced reaction is:
C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reactant and product participate in the reaction:
- C₃H₈: 1 mole
- O₂: 5 moles
- CO₂: 3 moles
- H₂O: 4 moles
Being the molar mass of each compound:
- C₃H₈: 44 g/mole
- O₂: 16 g/mole
- CO₂: 44 g/mole
- H₂O: 18 g/mole
Then, by stoichiometry, the following quantities of mass participate in the reaction:
- C₃H₈: 1 mole* 44 g/mole= 44 grams
- O₂: 5 moles* 16 g/mole= 80 grams
- CO₂: 3 moles* 44 g/mole= 132 grams
- H₂O: 4 moles* 18 g/mole= 72 grams
So you can apply the following rules of three:
- If by stoichiometry 1 mole of C₃H₈ forms 132 grams of CO₂, 2.55 moles of C₃H₈ how much mass of CO₂ will it form?

mass of CO₂= 336.6 grams
- If by stoichiometry 1 mole of C₃H₈ forms 72 grams of H₂O, 2.55 moles of C₃H₈ how much mass of H₂O will it form?

mass of H₂O= 183.6 grams
<u><em>336.6 grams of CO₂ and 183.6 grams of H₂O are formed from 2.55 moles of propane.</em></u>
Based on the information given, it should be noted that the ground-state electron configuration of carbon is 1s2 2s2 2p2.
<h3>
What is an electron?</h3>
Electrons are simply the subatomic particles which orbit the nucleus of an atom.
The arrangement of electrons in the atomic orbitals of an atom is known as the electron configuration. This can be determined by using a periodic table.
It should be noted that carbon is the sixth element with a total of 6 electrons in the periodic table. Thus, the atomic number Z = 6.
In conclusion, the ground-state electron configuration of carbon is 1s2 2s2 2p2.
Learn more about carbon on:
brainly.com/question/105003
Option (a) is correct.
A reducing agent is the one which loses electrons to other substance.
Here, Zn has oxidation number 0 in the L.H.S of the equation, but on R.H.S its oxidation number is +2 i.e. it Zn has donated two of its electrons to

.
Hence, Zn is the reducing agent here.