Let x,y be two different numbers
suppose x^2=y^2
then x^2-y^2=0
which yields (x+y)(x-y)=0
so either x=y or x=-y
In any case, x and y must be the same value
also when a vairable is squared like y=x^2
we must note that there are 2 possible solutions
x=(+/-)sqrt(y)
Step-by-step explanation:
a2+b2=c2 is phythagorean
Answer:
I think it's C
Step-by-step explanation:
A is go up one time
B is go down one time
C is... not sure what's going on there
And D is multiply by 8
I'm confused.
Answer:
1/3=0.33
Step-by-step explanation:
1/3=0.33333333
