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kondaur [170]
3 years ago
6

A scientist heats an unknown substance in a closed system. The graph shows the change in temperature over time. E D Temperature

C A Time During which period is the substance changing state? A. During the time labeled D, when the temperature stays the same B. During the time labeled E, when the temperature increases for a third time C. During the time labeled C, when the temperature increases ebarnly​
Chemistry
2 answers:
lilavasa [31]3 years ago
7 0

Answer: During The time labeled D, when the temperature stays the same

Explanation: none

Alika [10]3 years ago
6 0

Answer:I said During the time labeled A when the temperature first starts to increase

Explanation:

I will let you know if it’s right

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Plutonium−239 (t1/2 = 2.41 × 104 yr) represents a serious nuclear waste hazard. if seven half-lives are required to reach a tole
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The half-life of Plutonium−239, t1/2 is 2.41 × 10⁴<span> yrs

time taken to reach tolerable level = seven half-lives
                                                      = 7 x t1/2
                                                      = 7 x </span>2.41 × 10⁴ yrs
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5 0
3 years ago
Read 2 more answers
What is the freezing point of an aqueous solution that has 25.00 g of calcium iodide dissolved in 1250 g of water?
ozzi

Answer:

<u></u>

  • <u>- 0.380ºC</u>

Explanation:

The lowering of the freezing point of a solvent is a colligative property ruled by the formula:

  • \Delta T_f=K_f\times m\times i

Where:

  • ΔTf is the lowering of the freezing point
  • Kf is the molal freezing constant of the solvent: 1.86 °C/m
  • m is the molality of the solution
  • i is the van't Hoff factor: the number of particles (ions) per unit of ionic compound.

<u />

<u>a) molality, m</u>

  • m = number of moles of solute/ kg of solvent
  • number of moles of CaI₂ = mass in grams/ molar mass
  • number of moles of CaI₂ = 25.00g / 293.887 g/mol = 0.0850667mol
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<u>b) i</u>

  • Each unit of CaI₂, ideally, dissociates into 1 Ca⁺ ion and 2 I⁻ ions. Thus, i = 1 + 2 = 3

<u />

<u>c) Freezing point lowering</u>

  • ΔTf =  1.86 °C/m × 0.068053m × 3 = 0.3797ºC ≈ 0.380ºC

<h2>I have problems to upload the full answer in here, so I attach a pdf file with the whole answer.</h2>
Download pdf
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How is the potential (voltage) of a redox reaction determined using the reduction
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Answer:

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Explanation:

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