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3 years ago

Which part of an object's rate of change best defines acceleration?

Physics

2 answers:

likoan [24]3 years ago

7 0

Answer:

Velocity

Explanation: If you are going down hill, (Which is one direction) you will gain more speed by, gravity, friction, and most importantly velocity.

grandymaker [24]3 years ago

5 0

I believe it is speed.

Hope this helps!

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What should #1 be labeled?

aliya0001 [1]

B. North Pole because it’s pointing at the north pole, and not the others

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3 years ago

What is Newton first law?

Anit [1.1K]

Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force

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3 years ago

When the drivers pass each other, the driver of the red car is to toss a package of contraband to the other driver. To catch the

Brrunno [24]

Answer:

D=387.28m

Explanation:

At the moment where the toss is made $X_R = X_G$ , so we need both equations:

For the red car:

$X_R=\frac{a_R*t^2}{2}$ With initial speed of 0 and acceleration of 6.12m/s^2.

For the green car:

$X_G=Xo + V_G*t$ With $V_G = 60km/h*\frac{1000m}{1km} * \frac{1h}{3600s} = 16.66m/s$ and Xo = 200m

Since both positions will be the same:

$\frac{a_R*t^2}{2}=Xo+V_G*t$ Solving for t:

t1 = -5.8s and t1 =11.25s

Replacing t = 11.25 on either equation to find the displacement:

$D = X_R = \frac{a_R*t^2}{2} = 387.28m$

3 0

4 years ago

Which of the following statements is NOT true? A. You are exposed to nuclear radiation every day. B. Most of the nuclear radiati

tia_tia [17]

C is not true. Background radiation is the uniform microwave radiation remaining from the Big Bang.

5 0

3 years ago

One strategy in a snowball fight is to throw

Oxana [17]

second question: How many seconds after the first snowball

should you throw the second so that they

arrive on target at the same time?

Answer in units of s.

Answer:

Part 1: 28°

Part 2: 1.367

Explanation:

Part 1:

Given: 62°

Simple

θ = 90°- 62°

θ = 28°

Part 2:

Y-direction

Δy $=v_{yo} t+\frac{1}{2} a_{y} t^{2}$

$0=[16.2sin(62)]t_{1}+1/2(-9.8)t_{1}^{2} \\$

$t_{1} =\frac{2[16.2sin(62)]}{9.8}$

$t_{1}=2.91913s$

$0=[16.2sin(28)]t_{2}+1/2(-9.8)t_{2}^{2}$

$t_{2} =\frac{2[16.2sin(28)]}{9.8}$

$t_{2}=1.55213s$

Δt $=t_{1}-t_{2}$

Δt $=2.91913-1.55213$

Δt= 1.367s

Hope it helps :)

7 0

3 years ago