Weight = mass * gravity = 60 kg * 3.75 m/s² = 225 N
<span>Option D.</span>
F=mgsinα –F(fr)=
= mgsinα - μmgcosα
a=F/m =g(sinα – μcosα)
=9.8(sin14-0.57•cos14)= -3.04 m/s²
v²=v₀²+2ad
v=sqrt{ v₀²+2ad} =
=sqrt{18²+2• (-3.04) •25}=13.1 m/
Answer:
30.7m
Explanation:
You can use the following equation:
ρ = R * 
Where ρ is the resistivity, R is the resistance, S is the Cross-sectional Area and l is the length of the wire.
We issolate l in the equation and solve with the data we have:
l = R *
= 3.25 Ω *
l = 30.7m
Answer:
Explanation:
Energy store in the compressed trampoline = potential energy of at the maximum height ignoring friction
energy stored in the trampoline =
where k is spring constant and x is the distance compressed = 0.5 × 2900 × 0.38² = 209.38 J
209.38 J = 25 × 9.8 × h
h maximum height attain = 209.38 J / ( 25 × 9.8) = 0.855 m
Answer:If the forces on an object are balanced, the net force is zero.
Explanation:
If the forces are unbalanced forces, the effects don't cancel each other. Any time the forces acting on an object are unbalanced, the net force is not zero, and the motion of the object changes.