Answer:
The time taken by the projectile to hit the ground is 6.85 sec.
Explanation:
Given that,
Vertical height of cliff = 230 m
Distance = 300 m
Suppose, determine the time taken by the projectile to hit the ground.
We need to calculate the time
Using second equation of motion
Where, s = vertical height of cliff
u = initial vertical velocity
g = acceleration due to gravity
Put the value in the equation
Hence, The time taken by the projectile to hit the ground is 6.85 sec.
GPE I am assuming is gravitational potential energy. I'll denote it as U for simplicity.
U = mgy
U = (70kg)(9.81m/s^2)(1m) = 686.7J
U = 686.7J
Hope this helps!
Answer:
2 * 10^5 pa
Explanation:
Pressure = Force / Area
Each thigh bone has a cross sectional area of 10cm²
Both thigh bones :
2 * 10cm² = 20cm²
To m² : 20 * (0.01)²
20 * 0.0001 m² = 0.002 m²
Force = mass * acceleration due to gravity(g)
g = 10m/s² ;
Force = 40 * 10 = 400N
Pressure = 400 N / 0.002 m²
Pressure = 200,000 N/m² = 2 * 10^5 pascal
Answer:
27.1m/s
Explanation:
Given parameters:
Height of the building = 30m
Initial velocity = 12m/s
Unknown:
Final velocity = ?
Solution:
We apply one of the kinematics equation to solve this problem:
v² = u² + 2gh
v is the final velocity
u is the initial velocity
g is the acceleration due to gravity
h is the height
v² = 12² + (2 x 9.8 x 30)
v = 27.1m/s
