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Musya8 [376]
3 years ago
11

True or False.....When heat flows into matter, the enthalpy/heat of reaction and temp. will

Chemistry
1 answer:
rewona [7]3 years ago
4 0

Answer:

true I think but I am not sure

Explanation:

I hope it's help u :)

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Given the information that nitrogen atoms are larger than hydrogen atoms,which of the models best represent ammonia?(NH3)
Ray Of Light [21]

Answer:

<em>The correct option is the structure in the option D. </em>

Explanation:

Ammonia contains a single nitrogen atom bonded to three hydrogen atoms.

The structure present in option A shows a single nitrogen atom bonded with a single hydrogen atom hence it is not correct.

The structure in option B shows a nitrogen atom bonded to four hydrogen atoms hence it is also not correct.

The structure in option C shows a nitrogen atom bonded to two hydrogen atoms hence it is also not correct.

The structure in option D shows a nitrogen atom bonded to three hydrogen atoms which is the correct structure of ammonia (NH3).

4 0
3 years ago
The law of converservation of mass states of the mass to the reacant is
olganol [36]

Answer:

the same as the products.

Explanation:

Law of conservation of mass states that the mass of the reactant is always the same as the products since they are not lost nor gained.

5 0
3 years ago
Arrange the following in order of increasing bond strength of the carbon oxygen bond:
icang [17]

Answer: Option (d) is the correct answer.

Explanation:

It is known that length of a bond is inversely proportional to the bond strength. This also means that a single bond has long length due to which it is weak in nature.

And, a double bond is shorter in length and has more strength as compared to a single bond. Whereas a triple bond has the smallest length and it has high strength as compared to a double or single bond.

For example, carbon monoxide is CO where there is a triple bond between the carbon and oxygen atom.

Carbon dioxide is CO_{2} where there exists a double bond between the carbon and oxygen atom.

A carbonate ion is CO^{2-}_{3} when two oxygen atoms are attached through single bond with the carbon atom and another oxygen atom is attached through a double bond to the carbon atom.

Hence, we can conclude that order of increasing bond strength of the given carbon oxygen bond is as follows.

        Carbonate ion < carbon dioxide < carbon monoxide

5 0
3 years ago
How many neutrons are in Cesium-130 (Cs)? 55 75 130 185
Oksana_A [137]
There are 78 neutrons in Cesium but there is no option of 78 so closely related is 75 
4 0
4 years ago
An acid solution is 0.100 M in HCl and 0.210 M in H2SO4. What volume of a 0.150 M solution of KOH must be added to 500.0 mL of t
Dmitry_Shevchenko [17]

Answer:

When we add 0.33L of KOH only the HCl solution will be neutralized. When we add <u>1.4 L</u> of KOH, all of the acid (the HCl and H2SO4 solution) will be neutralized.

Explanation:

<u>Step 1:</u> Data given

The solution has 0.100 M HCl and 0.210 M H2SO4

Molarity KOH = 0.150 M

Volume of acid solution = 500 mL = 0.5 L

<u>Step 2: </u>Calculate moles of HCl

Moles HCl = Molarity HCl * volume

Moles HCl = 0.100 M * 0.5 L

Moles HCl = 0.05 moles

<u>Step 3:</u> Calculate moles of H2SO4

Moles H2SO4 = 0.210 M * 0.5 L

Moles H2SO4 = 0.105 moles

<u>Step 4:</u> The balanced neutralization reaction of KOH with HCl can be written as:

KOH + HCl → KCl + H2O

The mole ratio is 1:1

This means to neutralize 0.05 moles HCl, we need 0.05 moles KOH

<u>Step 5:</u> The balanced neutralization reaction of KOH with H2SO4 can be written as:

2KOH + H2SO4 → K2SO4 + 2H2O

The mole ratio KOH: H2SO4 is 2:1

This means to neutralize 0.105 moles H2SO4 we need 0.210 moles KOH

<u>Step 6: </u>Calculate volume of KOH needed to neutralize the solution

To neutralize the HCl solution: 0.05 moles / 0.150 M = 0.33 L KOH needed

To neutralize the H2SO4 solution: 0.210 moles / 0.150 M = 1.4 L KOH needed

When we add 0.33L of KOH the HCl solution will be neutralized. When we add 1.4 L of KOH the HCl and H2SO4 solution will be neutralized.

4 0
3 years ago
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