Answer:
a) Ba(NO₃)₂(aq) + (NH₄)₂SO₄(aq) ⇒ 2 NH₄NO₃(aq) + BaSO₄(s)
b) CoCl₃(aq) + 3 NaOH(aq) ⇒ 3 NaCl(aq) + Co(OH)₃(s)
c) 2 FeCl₃(aq) + 3 (NH₄)₂S(aq) ⇒ 6 NH₄Cl(aq) + Fe₂S₃(s)
Explanation:
We have 3 double displacement reactions, in which both reactants exchange their cations and anions, and an insoluble compound is formed and precipitates as a solid. This is indicated as (s).
a) Ba(NO₃)₂(aq) + (NH₄)₂SO₄(aq) ⇒ 2 NH₄NO₃(aq) + BaSO₄(s)
b) CoCl₃(aq) + 3 NaOH(aq) ⇒ 3 NaCl(aq) + Co(OH)₃(s)
c) 2 FeCl₃(aq) + 3 (NH₄)₂S(aq) ⇒ 6 NH₄Cl(aq) + Fe₂S₃(s)
Compound A will be 2-chloro-butane which in the presence of sodium methoxide will undergo the elimination of the halogen with a hydrogen from the neighboring atom carbon (not the one with which the halogen in bound), which have less hydrogen atoms, forming the trans-2-butene.
Answer:
THE answer is all of above
Explanation:
