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3 years ago

A 65 kg student sits 3 m away from a 70 kg student. What is the magnitude of the gravitational force between the two students?

Physics

1 answer:

LiRa [457]3 years ago

3 0

Answer:

$F=3.37\times 10^{-8}\ N$

Explanation:

Given that,

Mass of student 1, m₁ = 65 kg

Mass of student 2, m₂ = 70 kg

The distance between the students, d = 3 m

We need to find the magnitude of the gravitational force between the two students. The formula for the magnitude of the gravitational force between two masses is given by :

$F=G\dfrac{m_1m_2}{d^2}\\\\F=6.67\times 10^{-11}\times \dfrac{65\times 70}{(3)^2}\\F=3.37\times 10^{-8}\ N$

So, the gravitational force between the two students is $3.37\times 10^{-8}\ N$ .

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Answer:

Explanation:

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4 years ago

A tray containing 0.20kg of water at 20degree celsius is placed in a freezer. The temperature of the water drops to 0degree cels

Nitella [24]

Answer:

a. Energy lost, Q = 16,800 Joules.

b. Power = 28 J/s

c. Time, t = 2357.14 seconds

d. I assumed that the ice remained at a temperature of zero degrees Celsius (0°C). Also, I assumed that the heat is being lost at a constant rate.

Explanation:

Given the following data;

Mass = 0.20 kg
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Where;

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M represents the mass of an object.
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Substituting the values into the formula, we have;

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First of all, we would have to convert the value of time in minutes to seconds.

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3 years ago

Read 2 more answers

Conclusion on ohm's law experiment

Free_Kalibri [48]

Answer:

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