Question

A 65 kg student sits 3 m away from a 70 kg student. What is the magnitude of the gravitational force between the two students?

Answer 1

Answer:

$F=3.37\times 10^{-8}\ N$

Explanation:

Given that,

Mass of student 1, m₁ = 65 kg

Mass of student 2, m₂ = 70 kg

The distance between the students, d = 3 m

We need to find the magnitude of the gravitational force between the two students. The formula for the magnitude of the gravitational force between two masses is given by :

$F=G\dfrac{m_1m_2}{d^2}\\\\F=6.67\times 10^{-11}\times \dfrac{65\times 70}{(3)^2}\\F=3.37\times 10^{-8}\ N$

So, the gravitational force between the two students is $3.37\times 10^{-8}\ N$.