Answer:
The magnitude of car A acceleration is 4 times that of car E
Explanation:
Assuming they are traveling at a constant speed. Their (centripetal) acceleration is as the following
![a = \frac{v^2}{r}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7Bv%5E2%7D%7Br%7D)
where v is the (linear) velocity and r is the radius. We can use this to calculate their ratio
![a_A / a_E = \frac{v_A^2/r_A}{v_E^2/r_E} = \left(\frac{v_A}{v_E}\right)^2\frac{r_E}{e_A}](https://tex.z-dn.net/?f=a_A%20%2F%20a_E%20%3D%20%5Cfrac%7Bv_A%5E2%2Fr_A%7D%7Bv_E%5E2%2Fr_E%7D%20%3D%20%5Cleft%28%5Cfrac%7Bv_A%7D%7Bv_E%7D%5Cright%29%5E2%5Cfrac%7Br_E%7D%7Be_A%7D)
Since
and ![r_A = r_E](https://tex.z-dn.net/?f=r_A%20%3D%20r_E)
![a_A / a_E = 2^2 = 4](https://tex.z-dn.net/?f=a_A%20%2F%20a_E%20%3D%202%5E2%20%3D%204)
So the magnitude of car A acceleration is 4 times that of car E
I believe it is B wavelength
<span>The gravity of earth depends on the magnetism from its core. as this magnetism increases, the magnitude of the gravity increases.</span>