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2 years ago

Please help ASAP guys !!! Thanks

Physics

1 answer:

andreev551 [17]2 years ago

7 0

Answer:

(a) gravitational potential energy converted to kinetic energy

(b) chemical energy is converted to light or heat energy

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1. How far does a 70 kg object move in meters (m) if it

fenix001 [56]

Answer:

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3 years ago

Regarding the history of the universe, which of the following is true? Regarding the history of the universe, which of the follo

ale4655 [162]

Explanation:

1. The universe consisted of hydrogen and helium initially. This statement is true.

2. It is important to understand radioactive decay in order to understand this question, here's a good analogy:

A snake will shed it's skin, just as an atom will shoot off different parts of itself. It would be very difficult to force that snake to reenter it's skin once it sheds, just as it takes a lot of energy to force <em>fusion</em><em> </em>of atoms and the parts mentioned. In normal circumstances, nuclear decay is one-way.

3. The earth is a giant floating rock in space. It took many many years to gather a bunch of asteroids and dust to make this planet.

4. I shouldn't have to explain this one, it doesn't make much sense.

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3 years ago

Solving a series circuit, did I do this correctly?

nirvana33 [79]

The total resistance in the circuit is 16 Ohms.
The total current in the circuit is 0.5 Ampere.
The current at $R_1$ is 0.5 Ampere.
The current at $R_3$ is 0.5 Ampere.
The voltage drop at $R_1$ is 4 volts.
The voltage drop at $R_2$ is 2.5 volts.
The voltage drop at $R_3$ is 1.5 volts.
The total power consumed by the circuit is 4watts
The power consumed at $R_1$ is 2 watts
The power consumed at $R_2$ is 1.25 watts

Given:

The voltage across the circuit = V = 8 V

The resistors connected are in series:

$R_1=8 \Omega, R_2=5\Omega ,R_3=3 \Omega$

To find:

The values of from 1 to 10.

Solution

The voltage across the circuit = V = 8 V

The total resistance in the circuit = $R_{eq}$

$R_{eq}=R_1+R_2+R_3\\=8 \Omega +5 \Omega + 3\Omega =16\omega$

The total current in the circuit = I

$V=IR_{eq}\\I=\frac{V}{R_{eq}}=\frac{8 V}{16 \Omega}=0.5 A$ (Ohm's law)

For series combinations, the current in each resistor remains the same.

So, the current in $R_1, R_2 \&R_3$ :

$I_1= I_2= I_3=I=0.5 A\\$

The voltage drop across at $R_1$ = $V_1$

The current across $R_1$ = I = 0.5 A

$V_1=I\times R_1\\\\=0.5A\times 8\Omega = 4 V$

The voltage drop across at $R_2$ = $V_2$

The current across $R_2$ = I = 0.5 A

$V_2=I\times R_2\\\\=0.5A\times 5\Omega = 2.5 V$

The voltage drop across at $R_3$ = $V_3$

The current across $R_3$ = I = 0.5 A

$V_3=I\times R_3\\\\=0.5A\times 3\Omega = 1.5 V$

The total power consumed by circuit:

$P= V\times I \\\\= 0.5 A\times 8 V = 4 watt$

Power consumed at $R_1$ :

$P_1=V_1\times I\\\\= 4V\times 0.5A = 2 watt$

Power consumed at $R_2$ :

$P_2=V_2\times I\\\\= 2.5 V\times 0.5A = 1.25 watt$

Power consumed at $R_3$ :

$P_3=V_3\times I= \\\\1.5 V\times 0.5A = 0.75 watt$

Learn more about, current, voltage, resistance, and power of the circuit here:

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2 years ago

A 60 kg swimmer at a water park enters a pool using a 2 m high slide. Find the velocity of the swimmer

koban [17]

Answer:

the velocity of the swimmer at the bottom of the slide is 6.26 m/s

Explanation:

The computation of the velocity of the swimmer at the bottom of the slide is given below:

v = √2gh

= √2 × 9.8 × 2

= 6.26 m/s

Hence, the velocity of the swimmer at the bottom of the slide is 6.26 m/s

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3 years ago

Most of the mass of the Milky Way exists in the form of A. dust. B. stars. C. dark matter. D. gas.

OLga [1]

Answer:

C. Dark Matter

Explanation:

Dark matter is estimated to make up 90 percent of the mass of the galaxy.

The dark matter (as astronomers have come to call the invisible material) extends to a distance of at least 200,000 light-years from the center of the Galaxy.

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4 years ago