<h2>
Answer:</h2>
24Ω
<h2>
Explanation:</h2>
When resistors are connected in parallel, the reciprocal of their combined resistance, when read with a DMM (Digital Multimeter - for measuring various properties of a circuit or circuit element such as resistance...) is the sum of the reciprocals of their individual resistances.
For example if two resistors of resistances R₁ and R₂ are connected together in parallel, the reciprocal of their combined resistance Rₓ is given by;
= 
+ 
Solving for Rₓ gives;
= 
------------------(i)
From the question;
Let
R₁ = resistance of first resistor = 40Ω
R₂ = resistance of second resistor = 60Ω
Now,
To get their combined or total resistance, Rₓ, substitute these values into equation (i) as follows;
= 
= 
= 24 Ω
Therefore, the total resistance is 24Ω
Answer:
//Convert any decimal number to binary number
//Program is written in C++ Programming Language
// Comments are used for explanatory purpose
// Program starts here
#include <iostream>
using namespace std;
// Main Method declared here
int main()
{
int x;
cout<<"Enter any integer number: ";
cin>>x;
DecBin(x);
return 0;
}
// Here a function named DecBin is declared along with an integer variable, x
void DecBin(int x)
{
// Declare an array to store the resulting binary digits
int bindigit[32];
// counter for binary array
int kount = 0;
while (x > 0) {
// Store the remainder of each division in the declared array
bindigit[kount] = x % 2;
x = x / 2;
kount++;
}
// Loop to print the binary digits in reverse order
for (int j = i - 1; j >= 0; j--)
{
cout << bindigit[j];
}
}
// End of Program
Answer:
decreased
Explanation:
when impaired you react slower then you would sober.
Answer:
This is self locking.
Explanation:
Given that
Diameter d= 40 mm
Pitch (P)= 6 mm
Torque T= 1 KN.m
Friction(μ) = 0.1
Thread is double square.
Condition for self locking
L= n x P
N= number of start
Here given that double start so n=2
L=2 x 6 = 12 mm
(μ = 0.1)
So from we can that this is self locking.
Answer:
its so simple. u must mind some formulas.
Explanation:
mili->10^(-3)
micro->10^(-6)
nano->10^(-9)
so write the exact number and move "." to left or right depend question.
in this one:
23.5 is 23500000.0 nano with a default dot at the end
for turning to mili u must move the dot 6 steps to left so it will be: 23.5 milimeter.
