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Colt1911 [192]
3 years ago
11

A man is trying to push a 250 N dresser across his carpeted bedroom. He applies a force of 20 N and the carpet provides a fricti

onal force of 8N. Which vectors represented in the diagram below will you need to consider and what will be the resulting net force?

Physics
1 answer:
11111nata11111 [884]3 years ago
3 0

Answer:

The correct option is;

B. Subtract vectors A from C; F_{Net} = 12 N

Explanation:

The given parameters are;

The weight of the dresser = 250 N

The force applied by the man = 20 N = C

The frictional force provided by the carpet = 8 N = The component of the weight resisting motion = A

Therefore, the net force tending to put the dresser in motion, F_{Net}, is given as follows;

F_{Net} = The force applied by the man, C - The frictional force provided by the carpet which is the component of the weight resisting motion, A

F_{Net} = C - A = 20 N - 8 N = 12 N

F_{Net} = 12 N

The resulting net force, F_{Net} = 12 N.

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Compare and contrast area and volume
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6 0
3 years ago
A 15.0 kg crate, initially at rest, slides down a ramp 2.0 m long and inclined at an angle of 20.0° with the horizontal. Using t
Elis [28]

The component of the crate's weight that is parallel to the ramp is the only force that acts in the direction of the crate's displacement. This component has a magnitude of

<em>F</em> = <em>mg</em> sin(20.0°) = (15.0 kg) (9.81 m/s^2) sin(20.0°) ≈ 50.3 N

Then the work done by this force on the crate as it slides down the ramp is

<em>W</em> = <em>F d</em> = (50.3 N) (2.0 m) ≈ 101 J

The work-energy theorem says that the total work done on the crate is equal to the change in its kinetic energy. Since it starts at rest, its initial kinetic energy is 0, so

<em>W</em> = <em>K</em> = 1/2 <em>mv</em> ^2

Solve for <em>v</em> :

<em>v</em> = √(2<em>W</em>/<em>m</em>) = √(2 (101 J) / (2.0 m)) ≈ 10.0 m/s

3 0
3 years ago
* A ball is projected horizontally from the top of
bagirrra123 [75]

Explanation:

Given

Ball is projected horizontally from a building of height h=19.6\ m

time taken to reach ground is given by

\text{Cosidering vertical motion}\\\Rightarrow h=ut+0.5at^2\\\Rightarrow 19.6=0+0.5\times 9.8t^2\\\Rightarrow t^2=4\\\Rightarrow t=2\ s

(b) Line joining the point of projection and the point where it hits the ground makes an angle of 45^{\circ}

From the figure, it can be written

\Rightarrow \tan 45^{\circ}=\dfrac{h}{x}\\\\\Rightarrow x=h\cdot 1\\\Rightarrow x=19.6

Considering horizontal motion

\Rightarrow x=u_xt\\\Rightarrow 19.6=u_x\times 4\\\Rightarrow u_x=4.9\ m/s

(c) The vertical velocity with which it strikes the ground is given by

\Rightarrow v^2-u_y^2=2as\\\Rightarrow v^2-0=2\times 9.8\times 19.6\\\Rightarrow v=\sqrt{384.16}\\\Rightarrow v=19.6\ m/s

Thus, the ball strikes with a vertical velocity of 19.6\ m/s

6 0
3 years ago
Read 2 more answers
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