The answer is E. Short and thick while cold.
Answer:
b.
Explanation:
-vesign shows the lens is <em><u>C</u></em><em><u>O</u></em><em><u>N</u></em><em><u>C</u></em><em><u>A</u></em><em><u>V</u></em><em><u>E</u></em>
<em><u>f</u></em><em><u>=</u></em>1/power
Area is a region bounded by a CLOSED path, curved path or path with line segments. Area is usually a two dimensional physical quantity, a
designated part on a plane. An example the surface of a table, face of a
wall or a ceiling. It can also be a surface in 3-dimensions. Its units are meter² or centimeter² or feet² etc. A large agricultural field is a good example of an area. Normally and ideally no object can reside or exist with in an area. An object requires a volume. It is a collection of all points enclosed or bounded by the boundary or closed path. It does not have any thickness.
Volume is a 3-dimensional quantity. A physical body occupies space with its material components. It is the amount of space occupied, that is its volume. Any existing body occupying some space has a mass and volume. A mass having a volume, has surface area and thickness, a height perpendicular to its surface at each point on the surface.
It is expressed as meter³, feet³ etc.
Volume is a product of surface area (cross-section) and length - for example for a wire or rod.
The component of the crate's weight that is parallel to the ramp is the only force that acts in the direction of the crate's displacement. This component has a magnitude of
<em>F</em> = <em>mg</em> sin(20.0°) = (15.0 kg) (9.81 m/s^2) sin(20.0°) ≈ 50.3 N
Then the work done by this force on the crate as it slides down the ramp is
<em>W</em> = <em>F d</em> = (50.3 N) (2.0 m) ≈ 101 J
The work-energy theorem says that the total work done on the crate is equal to the change in its kinetic energy. Since it starts at rest, its initial kinetic energy is 0, so
<em>W</em> = <em>K</em> = 1/2 <em>mv</em> ^2
Solve for <em>v</em> :
<em>v</em> = √(2<em>W</em>/<em>m</em>) = √(2 (101 J) / (2.0 m)) ≈ 10.0 m/s
Explanation:
Given
Ball is projected horizontally from a building of height 
time taken to reach ground is given by

(b) Line joining the point of projection and the point where it hits the ground makes an angle of 
From the figure, it can be written

Considering horizontal motion

(c) The vertical velocity with which it strikes the ground is given by

Thus, the ball strikes with a vertical velocity of 