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Basile [38]
3 years ago
5

Which element is depicted from this orbital diagram? A NA N 3p 35 Increasing Energy A NA A 2p 2s 11 1s O Fluorine O Chlorine O N

eon Argon​
Chemistry
1 answer:
nordsb [41]3 years ago
3 0

Answer:

Explanation:

neon

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Which part of the cell does this illustration represent?
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Answer: Mitochondria. The mitochondria contains cristae.
6 0
3 years ago
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A student needs to convert a volume of 3 Tbsp (tablespoons) to mL. The student finds out that 1 tablespoon is equivalent to 14.7
garri49 [273]

Answer:

The conversion factor is 14.79 mL/Tbsp.

Explanation:

To do an unity conversiton, we can make a factor by a ratio transformation:

3 Tbsp * \frac{14.79 mL}{1Tbsp}

So, the conversion factor is 14.79 mL/Tbsp and 3 Tbsp has 44.37 mL.

3 0
2 years ago
Lionel has a hot plate, a thermometer, a container of water, a spoon, and a small hammer. Using these tools,
DIA [1.3K]

Answer:

atomic structure

Explanation:

Its pretty obvious. Nothing here can test atomic structure. You can test melting point, with a hot plate. You can test the ability to dissolve something with the container of water. You can test brittleness  with the hammer.

6 0
3 years ago
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The formation of SO3 from SO2 and O2 is an intermediate step in the manufacture of sulfuric acid, and it is also responsible for
jeka57 [31]

Answer:

118.22 atm

Explanation:

2SO₂(g) + O₂(g) ⇌ 2SO₃(g)      

KP = 0.13 = \frac{p(SO_{3})^{2}}{p(SO_{2})^{2}p(O_{2})}

Where p(SO₃) is the partial pressure of SO₃, p(SO₂) is the partial pressure of SO₂ and p(O₂) is the partial pressure of O₂.

  • With 2.00 mol SO₂ and 2.00 mol O₂ if there was a 100% yield of SO₃, then 2 moles of SO₃ would be produced and 1.00 mol of O₂ would remain.
  • With a 71.0% yield, there are only 2*0.71 = 1.42 mol SO₃, the moles of SO₂ that didn't react would be 2 - 1.42 = 0.58; and the moles of O₂ that didn't react would be 2 - 1.42/2 = 1.29.

The total number of moles is 1.42 + 0.58 + 1.29 = 3.29. With that value we can calculate the molar fraction (X) of each component:

  • XSO₂ = 0.58/3.29 = 0.176
  • XO₂ = 1.29/3.29 = 0.392
  • XSO₃ = 1.42/3.29 = 0.432

The partial pressure of each gas is equal to the total pressure (PT) multiplied by the molar fraction of each component.

  • p(SO₂) = 0.176 * PT
  • p(O₂) = 0.392 * PT
  • p(SO₃) = 0.432 * PT

Rewriting KP and solving for PT:

\frac{p(SO_{3})^{2}}{p(SO_{2})^{2}p(O_{2})}=0.13\\\frac{(0.432*P_{T})^{2}}{(0.176*P_{T})^{2}(0.392*P_{T})} =0.13\\\frac{0.1866*P_{T}^{2}}{0.0121*P_{T}^{3}} =0.13\\\frac{15.369}{P_{T}}=0.13\\P_{T}=118.22 atm

5 0
3 years ago
Hydrocarbons containing only single bonds between the carbon atoms are called?
umka21 [38]

Answer:

Alkanes

Explanation:

Alkanes are hydrocarbons containing only single bonds between the parent chain carbons.

Alkenes are hydrocarbons containing at least one double bond between the parent chain carbons.

Alkynes are hydrocarbons containing at least one triple bond between the parent chain carbons.

7 0
1 year ago
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