What are two important uses of petroleum
2 answers:
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Answer:
The speed of the sled is 3.56 m/s
Explanation:
Given that,
Mass = 2.12 kg
Initial speed = 5.49 m/s
Coefficient of kinetic friction = 0.229
Distance = 3.89 m
We need to calculate the acceleration of sled
Using formula of acceleration
Where, F = frictional force
m = mass
Put the value into the formula
We need to calculate the speed of the sled
Using equation of motion
Where, v = final velocity
u = initial velocity
a = acceleration
s = distance
Put the value in the equation
Hence, The speed of the sled is 3.56 m/s.
Answer:
(a) x = 0.25 m
(b) v = 1.46 m/s
(c) v = 2.4 m/s
Explanation:
mass (m) = 10.3 kg
force from thrust (F) = 240 N
spring constant (k) = 400 N/m
stretch distance from thrust (y) = 30 cm = 0.3 m
acceleration due to gravity (g) = 9.8 m/s^{2}
(A) from mg = kx
compression (x) = mg/ k
x =
x = 0.25 m
(B) from the conservation of forces
(Fy) + (0.5k) = (0.5k
) + mgh + (0.5m
)
v = ) - (0.5k
) - mgh }{0.5m}[/tex]}[/tex]
v = ) - (0.5 x 400 x
) - (10.3 x 9.8 x (0.25 + 0.3)) }{0.5 x 10.3}[/tex]}[/tex]
v = 1.46 m/s
(C) if the rocket weren't attached to the spring, the conservation of energy equation becomes
(Fy) + (0.5k) = mgh + (0.5m
)
v = ) - mgh }{0.5m}[/tex]}[/tex]
v = ) - (10.3 x 9.8 x (0.25 + 0.3)) }{0.5 x 10.3}[/tex]}[/tex]
v = 2.4 m/s