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Afina-wow [57]
2 years ago
6

X = 1/2 a t square Help me please

Physics
1 answer:
S_A_V [24]2 years ago
5 0
How can I help? What’s the question?
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An acorn with a mass of 0.300 kilograms falls from a tree. What is its kinetic energy when it reaches a velocity of 5.oo m/s?
vladimir1956 [14]

Answer: 3.75 joules

Explanation:

Given that:

Mass of acorn = 0.300 kilograms

velocity = 5.oo m/s

Kinetic energy = ?

Since, kinetic energy is the energy possessed by a moving object, its value depends on the mass M and velocity V of the acorn.

Thus, Kinetic energy = 1/2 x mv^2

= 1/2 x 0.300kg x (5.00m/s)^2

= 0.5 x 0.3kg x (5.00m/s)^2

= 0.15 x (5.00m/s)^2

= 3.75 joules

Thus, the kinetic energy of the falling acorn is 3.75 joules

5 0
2 years ago
What are sun spots??????????
babymother [125]
Sunspots<span> are temporary phenomena on the </span>Sun<span>'s photosphere that appear as </span>spots<span> darker than the surrounding areas. They are regions of reduced surface temperature caused by concentrations of magnetic field flux that inhibit convection. </span>Sunspots<span> usually appear in pairs of opposite magnetic polarity.

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4 0
3 years ago
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Both the Moon and the Sun influence the tides on Earth. The moon has a much greater influence though. Why is that? A) because th
Temka [501]
C. The sun is 400 times farther from Earth than the moon is.
3 0
2 years ago
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The first confirmed detections of extrasolar planets occurred in ____________. The first confirmed detections of extrasolar plan
nirvana33 [79]

Answer:

1992 (Early 1990s)

Explanation:

First of all, i would like to define an extrasolar planet as a planet that orbits a start that is not our own.

The first confirmed detections of extrasolar planets occured in the early 1990s (specifically 1992, some say 1995). The name of the first extrasolar planet is widely believed to be called Dimidium or 51 Pegasi b.  

Extrasolar were searched by monitoring stars for slight dimming that might occur as unseen planets pass in front of them.

4 0
3 years ago
A worker pushes a box across the floor to the right at a constant speed with a force of 25N. What
icang [17]

Answer:

Friction between the box and the floor is 25N to the left

Explanation:

There are two forces acting on the box along the horizontal direction:

- The force of push applied by the worker, in the forward direction, F

- The force of friction, F_f, acting in the opposite direction (backward)

So the net force acting on the box is

F_{net}=F-F_f

According to Newton's second law of motion, the net force on an object is equal to the product between its mass (m) and its acceleration (a), so we can write:

F_{net}=ma

And so

F-F_f = ma

However, in this case the box is moving at constant speed; this means that its acceleration is zero:

a=0

Therefore we have:

F-F_f=0

Which means

F_f=F

And since we are told that

F=25 N

This means that the force of friction is also 25 N:

F_f=F=25 N

6 0
3 years ago
Read 2 more answers
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